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ohaa [14]
3 years ago
10

Brainliest to right answer any trolling will get you reported

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
5 0
Parent Function: f(x)=x*2

Horizontal Shift: None

Vertical Shift: Down 1 Units

Reflection about the x-axis: None

Reflection about the y-axis: None

Vertical Compression or Stretch: None
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What are the next 6 terms 1,3,9,27 ?
Triss [41]
Next 6 terms =81 ,243,729,2187,6561,19683
4 0
3 years ago
(THIS IS WORTH MANY POINTS, AND I’LL GIVE BRAINLIEST)
olganol [36]

9514 1404 393

Answer:

  • perimeter ratio: 4 : 3
  • area ratio: 16 : 9

Step-by-step explanation:

The ratio of perimeters is the ratio of corresponding sides.

  first : second = 8 : 6 = 4 : 3 . . . ratio of perimeters

The ratio of areas is the square of the ratio of linear dimensions.

  first : second = 4² : 3² = 16 : 9 . . . ratio of areas

5 0
3 years ago
Read 2 more answers
Cheryl collected data for her mathematics project. She noted that the data set was approximately normal.
nadya68 [22]

Answer:

X_(r) >> X_(n)

The mean for this case would increase since is defined as:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

The interquartile range would not change since the definition for the IQR is IQR =Q_3 -Q_1 and the quartiles are the same.

The standard deviation would not remain the same since by definition is:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And since we change the largest value the deviation would increase considerably.

And for the last option is not always true since if we select a value so much higher then the distribution would be skewed to the right.

So the best option for this case is:

Mean would increase.

Step-by-step explanation:

For this case we assume that we have a random sample given X_(1), X_(2) ,..., X_(n) and for each observation X_i \sim N(\mu, \sigma) since the problem states that the data is approximately normal.

Let's assume that the largest value on this sample is X_(n) and for this case we are going to replace this value by another one extremely higher so we satisfy this condition:

X_(r) >> X_(n)

The mean for this case would increase since is defined as:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

The interquartile range would not change since the definition for the IQR is IQR =Q_3 -Q_1 and the quartiles are the same.

The standard deviation would not remain the same since by definition is:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And since we change the largest value the deviation would increase considerably.

And for the last option is not always true since if we select a value so much higher then the distribution would be skewed to the right.

So the best option for this case is:

Mean would increase.

6 0
3 years ago
Simplify the expression below. (x5)(x2)
sp2606 [1]
Mutiply straight across 10x
8 0
3 years ago
A line contains the points S (4, -10) and B (10, -16). Find the slope of SB ̅̅̅̅. Must show your work to receive full credit
Alborosie

Answer:

The slope for this is -1.

Step-by-step explanation:

<em>First you want to put down the formula:</em>

<em><u>y^2 - y^1</u></em>

<em>x^2 - x^1</em>

<em>Fill it out and get your answer. </em>

<em>x^1=4</em>

<em>y^1=-10</em>

<em>x^2=10</em>

<em>y^2=-16</em>

<em>-belle :)</em>

7 0
3 years ago
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