All categories

3 years ago

Which of the following is the solution of One-fourth x + 5 = 7?

Mathematics

1 answer:

True [87]3 years ago

8 0

Answer:

x/4 + 5 = 7

-5 -5

x/4 = 2

*4 *4

x=8

Step-by-step explanation:

You might be interested in

Find the length of AC

mina [271]

The answer is 8 yd.. :)

5 1

3 years ago

The size your dog and the number of times you take it to the vet, The amount your drive to school and the amount you have to pay

Naddik [55]

Answer:

Negative, i think

5 0

2 years ago

Read 2 more answers

Find 0,8,3 round the nearest degree

MArishka [77]

The measure of $\theta$ is 68 degrees

<h3>How to solve the angle?</h3>

The complete question is in the attached image

The value of $\theta$ is calculate using the following cosine function

$\cos(\theta) = \frac 38$

Evaluate the quotient'

$\cos(\theta) = 0.375$

Take the arc cos of both sides

$\theta = \cos^{-1}(0.375)$

Evaluate the arc cos

$\theta = 67.97$

Approximate to the nearest degree

$\theta = 68$

Hence, the measure of $\theta$ is 68 degrees

Read more about right triangles at:

brainly.com/question/2437195

#SPJ1

3 0

2 years ago

on square bcde if e is located at (4,-9) and d is located at (10,-5) find the perimeter of the square

mariarad [96]

Answer:

8 $\sqrt{13}$ units

Step-by-step explanation:

P = 4a

<u>We can find one side by distance formula:</u>

a = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
a = $\sqrt{(10 - 4)^2+(-5+9)^2} = \sqrt{36+16} = \sqrt{52} = 2\sqrt{13}$

<u>Then the perimeter is:</u>

P = 4*2 $\sqrt{13}$ = 8 $\sqrt{13}$ units

5 0

3 years ago

Paired t‐Test for Mean Comparison with Dependent Samples To study the effects of an advertising campaign at a supply chain, seve

Lapatulllka [165]

Answer:

a) $t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{0.7 -0}{\frac{0.678}{\sqrt{5}}}=2.308$

$p_v =P(t_{(4)}>2.308) =0.0411$

So the p values is lower than the significance level given 0.05, so then we can conclude that we reject the null hypothesis.

b) The p value is illustrated on the figure attached.

If we select $\alpha=0.01$ we see that $p_v >\alpha$ so then we have enough evidence to FAIL to reject the null hypothesis.

Step-by-step explanation:

Part a

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.

Let put some notation

1=test value old , 2 = test value new

1: 5.2 6.5 7.2 5.7 7.6

2: 6.4 7.8 6.8 6.5 8.2

The system of hypothesis for this case are:

Null hypothesis: $\mu_2- \mu_1 \leq 0$