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miskamm [114]
2 years ago
10

Write √(-12) in simplest radical form

Mathematics
1 answer:
snow_lady [41]2 years ago
3 0

Answer:  2i\sqrt{3}

where i = \sqrt{-1}

====================================================

Work Shown:

x = \sqrt{-12}\\\\x = \sqrt{-1*4*3}\\\\x = \sqrt{-1}*\sqrt{4}*\sqrt{3}\\\\x = i*2*\sqrt{3}\\\\x = 2i\sqrt{3}\\\\

Therefore, \sqrt{-12} = 2i\sqrt{3}

------------

Explanation:

The basic steps are to factor the radicand such that we pull out the -1 and we also pull out the largest perfect square factor. That way we can then apply the rule \sqrt{A*B} = \sqrt{A}*\sqrt{B} to break up the root and simplify.

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Plugging values in formula, we get

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\mathrm{Divide\:both\:sides\:by\:}300

\frac{300\left(1+r\right)^2}{300}=\frac{329.49}{300}

\left(1+r\right)^2=1.0983

Taking square root on both sides, we get

1+r=\sqrt{1.0983}

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r=1.048-1

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3 years ago
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