Answer:
I'm going to use the Pythagoras theorem
1. hypotenus²= base²+height²
h²=80²+18²
h²=6400+324
√h²=√6724
hypotenuse= 82
2. 53²=45²+h²
2809=2025+h²
2809-2025=h²
784=h²
√784=√h²
h=28
3. 40²=b²+24²
1600=b²+576
1600-576=b²
√1024=√b²
b= 32
I'm just going to assume you're given the volume and LMNO are sides of the parallelogram
Area = LMNO
M=?
M=
Answer:
91.8 ft
Step-by-step explanation:
So we can talk about the diagram, let's name a couple of points. The base of the tree is point T, and the top of the tree is point H. We want to find the length of TH given the length AB and the angles HAT and ABT.
The tangent function is useful here. By its definition, we know that ...
TA/BA = tan(∠ABT)
and
TH/TA = tan(∠HAT)
Then we can solve for TH by substituting for TA. From the first equation, ...
TA = BA·tan(∠ABT)
From the second equation, ...
TH = TA·tan(∠HAT) = (BA·tan(∠ABT))·tan(∠HAT)
Filling in the values, we get ...
TH = (24.8 ft)tan(87.3°)tan(9.9°) ≈ 91.8 ft
The height <em>h</em> of the tree is about 91.8 ft.
Answer:
<h2>135° angle</h2>
Let the angle be x it's supplement = (180-x)
x = 3 (180-x)
⇒x=540−3x
⇒4x=540⇒x=135°
Step-by-step explanation:
Hope it is helpful....
