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NemiM [27]
2 years ago
8

Select the correct answer. Which fraction converts to a repeating decimal number? 1/12 7/8 14/25 17/20. 6/10 ​

Mathematics
1 answer:
djyliett [7]2 years ago
6 0

Answer:

\frac{7}{8}

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Original price: $64; Markup: 15% what is the retail price?
Brrunno [24]

Answer:

$73.60

Step-by-step explanation:

Original price:  $64

Markup:  0.15($64) = $9.60

New retail price:  $64 + $9.60 = $73.60

4 0
3 years ago
Which is the value of x in the equation?<br> 4(x-3) = 40
mario62 [17]

Answer:14

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Subtract three-forths from 2 times p
Savatey [412]

Answer:

Hi there!

Your answer is:

2p - 3/4

Hope this helps!

5 0
3 years ago
A random sample of 49 lunch customers was taken at a restaurant. The average amount of time the customers in the sample stayed i
Hunter-Best [27]

Answer:

a)  σ/√n= 1.43 min

c) Margin of error 2.8028min

d) [30.1972; 35.8028]min

e) n=62 customers

Step-by-step explanation:

Hello!

The variable of interest is

X: Time a customer stays at a restaurant. (min)

A sample of 49 lunch customers was taken at a restaurant obtaining

X[bar]= 33 mi

The population standard deviation is known to be δ= 10min

a) and b)

There is no information about the distribution of the population, but we know that if the sample is large enough, n≥30, we can apply the central limit theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;σ²/n)

Where μ is the population mean and σ²/n is the population variance of the sampling distribution.

The standard deviation of the mean is the square root of its variance:

√(σ²/n)= σ/√n= 10/√49= 10/7= 1.428≅ 1.43min

c)

The CI for the population mean has the general structure "Point estimator" ± "Margin of error"

Considering that we approximated the sampling distribution to normal and the standard deviation is known, the statistic to use to estimate the population mean is Z= (X[bar]-μ)/(σ/√n)≈N(0;1)

The formula for the interval is:

[X[bar]±Z_{1-\alpha /2}*(σ/√n)]

The margin of error of the 95% interval is:

Z_{1-\alpha /2}= Z_{1-0.025}= Z_{0.975}= 1.96

d= Z_{1-\alpha /2}*(σ/√n)= 1.96* 1.43= 2.8028

d)

[X[bar]±Z_{1-\alpha /2}*(σ/√n)]

[33±2.8028]

[30.1972; 35.8028]min

Using a confidence level of 95% you'd expect that the interval [30.1972; 35.8028]min contains the true average of time the customers spend at the restaurant.

e)

Considering the margin of error d=2.5min and the confidence level 95% you have to calculate the corresponding sample size to estimate the population mean. To do so you have to clear the value of n from the expression:

d= Z_{1-\alpha /2}*(σ/√n)

\frac{d}{Z_{1-\alpha /2}}= σ/√n

√n*(\frac{d}{Z_{1-\alpha /2}})= σ

√n= σ* (\frac{Z_{1-\alpha /2}}{d})

n=( σ* (\frac{Z_{1-\alpha /2}}{d}))²

n= (10*\frac{1.96}{2.5})²= 61.47≅ 62 customers

I hope this helps!

3 0
2 years ago
The population of birds in a sanctuary increases at a steady rate. The graph of the population over time has the points (1, 105)
Oksanka [162]
(1,105),(3,315)
slope = (315 - 105) / (3 - 1) = 210/2 = 105

y = mx + b
slope(m) = 105
use either of ur points....(1,105)...x = 1 and y = 105
now we sub and find b, the y int
105 = 1(105) + b
105 = 105 + b
105 - 105 = b
0 = b
so ur equation is : y = 105x + 0 which can be written as y = 105x

now to find a point on the line, sub in any number for x and solve for y
y = 105x....subbing in 2 for x
y = 105(2)
y = 210....so another point on the line is (2,210).....thats just one point, u can find more if u want....just sub in any number for x and solve for y
5 0
3 years ago
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