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2 years ago

Helen Sanchez's checking account had a balance of $678.22. She wrote a check to pay her gasoline charge

Mathematics

1 answer:

user100 [1]2 years ago

4 0

The answer to the question is $488.30 all you had to do was subtract

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When putting a number into scientific notation, the number you use must be between what two numbers?

Goshia [24]

Answer:

1 and 10

Step-by-step explanation:

can't be less than 1 but can't be more than 10

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3 years ago

What is the solution to the system of equations below?

Lemur [1.5K]

I think the answer is a

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3 years ago

PLEASE HELP FAST

IceJOKER [234]

-4,-9 I took the test and got the same answer.

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3 years ago

A fossil was analyzed and determined to have a carbon-14 level that is 80 % that of living organisms. the half-life of c-14 is 5

liq [111]

Answer:

The fossil is 1860 years old.

Step-by-step explanation:

The equation for the amount of fossil has the following format:

$Q(t) = Q(0)e^{rt}$

In which Q(t) is the amount after t years, Q(0) is the initial amount and r is the rate of change.

Half-life of c-14 is 5730 years.

This means that $Q(5730) = 0.5Q(0)$

$Q(t) = Q(0)e^{rt}$

$0.5Q(0) = Q(0)e^{5730r}$

$e^{5730r} = 0.5$

$\ln{e^{5730r}} = \ln{0.5}$

$5730r = \ln{0.5}$

$r = \frac{\ln{0.5}}{5730}$

$r = -0.00012$

$Q(t) = Q(0)e^{-0.00012t}$

How old is the fossil?

This is t for which

$Q(t) = 0.8Q(0)$

$Q(t) = Q(0)e^{-0.00012t}$

$0.8Q(0) = Q(0)e^{-0.00012t}$

$e^{-0.00012t} = 0.8$

$\ln{e^{-0.00012t}} = \ln{0.8}$

$-0.00012t = \ln{0.8}$

$t = -\frac{\ln{0.8}}{-0.00012}$

$t = 1860$

The fossil is 1860 years old.

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3 years ago

A fair number cube with

malfutka [58]

Answer:

b=15 percentage

a=20 percentage

6 0

3 years ago