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bezimeni [28]
3 years ago
5

Write an expression to 3(7 + 4g)

Mathematics
1 answer:
mafiozo [28]3 years ago
4 0

Answer:

Step-by-step explanation:

21+12g

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Another strategy for graphing a piecewise function is to use a table of values. The table below has a column for the input value
ELEN [110]

Answer:

Step-by-step explanation:

Q&A. Can more than one formula from a piecewise function be applied to a value in the domain? No. Each value corresponds to one equation in a piecewise formula.

6 0
3 years ago
"what is the probability that neither a nor b will happen?"
pshichka [43]
2 out of 26 cause theres 26 letters in the alphabet
7 0
3 years ago
Can you show the working out as well please?​
Airida [17]

Answer:

BC = 60

Step-by-step explanation:

3X + X = 80      <---- X = BC

3X + X = 4X

4X = 80   <---- DIVIDE BOTH SIDES BY 4

4X ÷ 4 = X

80 ÷ 4 = 20

20 × 3 = 60

6 0
3 years ago
Read 2 more answers
If you understand this could you please help me!
Vsevolod [243]

Answer:

Step-by-step explanation:

Area of shaded region = Area of quadrant - area of triangle

                                     = (1/4)πr² - (1/2)bh

                                   =\frac{1}{4}*3.14*5*5-\frac{1}{2}*5*5\\\\=19.625 - 12.5\\\\= 7.125\\\\

                                   = 7 cm²

4 0
3 years ago
SOME ONE HELP ME I REALLY NEED A SOLUTION FOR THIS PROBLEM WITH A CLEAR EXPLANATION
Sergio [31]

I'm going to answer this question using logic.  Let x be Jenny's favorite number.  We are going to square root this number, \sqrt{x} and then multiply it by \sqrt{2}.

This product needs to be an integer.  How is that obtainable? To be an integer, we need to get rid of the nasty \sqrt{2} part.  The only way I can think of to get rid of it, is to multiply it by \sqrt{2}, because \sqrt{2} *\sqrt{2} = 2.  Thus we have some conditions we need to fulfill when choosing Jenny's favorite number.

When we take the square root of Jenny's favorite number, x, it must contain a perfect square and a 2 in its prime factorization.  For example, 8 works because 8 = 2 x 2 x 2, or 2² x 2.  

You notice 8 is made up of a perfect square multiplied by 2.  So when we take the square root of 8, we get:

\sqrt{8} = \sqrt{2^{2}*2 } = \sqrt{ 2^{2} }*\sqrt{2} = \sqrt{4} *\sqrt{2} = 2*\sqrt{2}

So 8 is the same thing as 2\sqrt{2}

So when we multiply this by \sqrt{2}, we will get an integer! So as long as Jenny's favorite number consists of a perfect square and two in its prime factorization, we will have an integer!

So possible choices are: 2,8,18.

Why does 18 work? Because \sqrt{18} = \sqrt{9}* \sqrt{2} = 3\sqrt{2}

When we multiply this by \sqrt{2}, we get 6, which is an integer.

b) Suppose instead of multiplying by \sqrt{2}, we divided by \sqrt{2}. Is the resulting quotient still an integer?

YES, because we can get rid of the \sqrt{2} part by dividing by \sqrt{2} as well.  This leaves only the "perfect square" part left in our square root, and obviously a perfect square is an integer when we square root it.

I hope that made sense! (⌐■_■)

3 0
3 years ago
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