Given \qquad \overline{OA}\perp\overline{OC} OA ⊥ OC start overline, O, A, end overline, \perp, start overline, O, C, end overli
1 answer:
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Answer:
Large baking dish of cylinder, cone and sphere.
Step-by-step explanation:
When we compute the volume of each of the small and large baking dish taking =3.14, we get
Volume of cylinder (small dish)= (r^2)(h)
=3.14()^2*3
=
= 21.195
Volume of cylinder (large dish)= (r)^2(h)= 3.14*(3)^2(3)
=84.78
Similarly, volume of cone (smaller dish)=
= 7.065
Volume of cone (larger dish)= 84.78
Volume of sphere(smaller dish)=
= 14.13
Volume of sphere (larger dish) = 85.17 (approx)
Hence, we get that larger baking dish have approximately same volume.
Therefore, large baking dish of cylinder, cone, sphere will be chosen.
If you can't read it, I'll do my best to translate:
Z) 10^2 + 5^2 = 125
√125 = 11.18 = Z
Y) tan-1(5/10) = 26.57°
90 + 26.57 = 116.57
180 - 116.57 = 63.43°
5 ÷ sin(63.43) = 8.88 = Y
X) 11.18^2 + 8.88^2 = 203.8468
√203.8468 = 14.28
14.28 - 10 = 4.28 = x
All numbers are rounded to 2 decimal places, if you need any explanations for why I did something then just let me know :)
I hope this helps!
Z) 10^2 + 5^2 = 125
√125 = 11.18 = Z
Y) tan-1(5/10) = 26.57°
90 + 26.57 = 116.57
180 - 116.57 = 63.43°
5 ÷ sin(63.43) = 8.88 = Y
X) 11.18^2 + 8.88^2 = 203.8468
√203.8468 = 14.28
14.28 - 10 = 4.28 = x
All numbers are rounded to 2 decimal places, if you need any explanations for why I did something then just let me know :)
I hope this helps!