The percentage of data that is roughly greater than 66, as displayed in the box plot, is 100%.
<h3>How to Determine a Percentage of a Data Represented in a Box Plot?</h3>
In a box plot, we have the following displayed five-number summary which tells what percentage of the data distribution for each part of the data distribution:
Upper quartile (Q3): This is the value at where the box in the box plot ends at the edge of the box. From this point to the left, all data values that fall within the bracket make up 75% of the data.
Lower quartile (Q3): This is the value at where the box in the box plot starts at the edge of the box. From this point to the left, all data values that fall within the bracket make up 25% of the data.
Median: this is the middle value at the point where the line divides the box and data below this point make up 50% of the data.
The other five-number summary are the maximum and the minimum values that are represented by the whiskers.
On the box plot given, 66 is at the extreme whisker at the left. This means that the percentage of data that is roughly greater than 66 is 100%.
Learn more about the box plot on:
brainly.com/question/14277132
#SPJ1
Answer:
Step-by-step explanation:
y<4
These are how the graphs will look, they are color coded so have a look at the equations first.
Answer:
Step-by-step explanation:
I thought of a 2 digit number. The digits of my number are different: [XY]
Then I'm lost. Does "The unit digit of my number is the tens digit raised third power" mean that the X is raised to the third power?:
X^3
But then we need more information. X could be 1, 2,3, or 4. At 5 it becomes a three digit number. All of the other option result in a two digit number with different digits, so all seem possible. I don't know how to answer this without more information.
Answer:
y=-3
Step-by-step explanation:
function of line: y=mx+c
find the slope first;
y=-3,y0=-3,x=2,x0=-4
m=(y-y0)/(x-x0)
m=(-3-(-3))/(2-(-4))
m=(-3+3)/(2+4)
m=0/6
m=0.
y=mx+c, m=0, (use either of the points), i am using (2,-3)
-3=0*(2)+c
c=-3
y=mx+c, m=0, c=-3
y=0*x+(-3)
y=-3.