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Ugo [173]
2 years ago
8

I thought of a 2 digit number. The digits of my number are different. The unit digit of my number is the tens digit raised their

d power. What is my number?
Mathematics
1 answer:
ira [324]2 years ago
6 0

Answer:

Step-by-step explanation:

I thought of a 2 digit number. The digits of my number are different:  [XY]

Then I'm lost. Does "The unit digit of my number is the tens digit raised third power" mean that the X is raised to the third power?:

X^3

But then we need more information.  X could be 1, 2,3, or 4.  At 5 it becomes a three digit number.  All of the other option result in a two digit number with different digits, so all seem possible.  I don't know how to answer this without more information.

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A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic
goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event <em>E</em>_{i}, of the sample space <em>S,</em> given that another event <em>A</em> has already occurred is:

P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}

The law of total probability states that, if events <em>E</em>₁, <em>E</em>₂, <em>E</em>₃... are parts of a sample space then for any event <em>A</em>,

P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}

Denote the events as follows:

<em>X</em> = fetus have a chromosome abnormality.

<em>Y</em> = the test is positive

The information provided is:

P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85

Using the above the probabilities compute the remaining values as follows:

P(X^{c})=1-P(X)=1-0.04=0.96

P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10

P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})

          =(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}

             =\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}

             =0.20

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

6 0
3 years ago
Evaluate -6(x-2y) when x= -3 and y= -5<br> a. -42<br> b. 80<br> c. -80<br> d. -16
Vinil7 [7]
Simply substitute x for -3 and y for -5, creating the equation shown below:
     
     -6 (-3 - 2(-5) )
Now that you have your values set up, now you can do the math by starting off with Multiplying -2 by -5, which will get you 10. 

Now that you have the parenthesis simplified in the parenthesis, you can use the distributive property by multiplying all the numbers with -6, like so:
-6(-3+10)= 18 - 60, which simplifies to -42, in which (A) is your answer.
 
 
5 0
3 years ago
Read 2 more answers
A group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. If they randomly decide who will
frutty [35]

Answer:

B. 0.268

Step-by-step explanation:

if there are more than half boys then girls it as t be und .5 since that's half and .018 is to low

3 0
2 years ago
How to simplify this
algol [13]
To simplify this, you would have to turn b^-2 into a positive exponent.
To do this, we have to flip b^-2, which would get rid of the negate from the exponent: -2

3a^4 b^-2 c^3 / b^-2

Then we get the answer:

3a^4 c^3
------------
   b^-2

I have a picture to clarify! 
I hope this helped, let me know if you don't understand! ^.^

6 0
2 years ago
Two planes that do not intersect are parallel
frez [133]

True.  If they never intersect then they must have the same slope and are parallel

6 0
3 years ago
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