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ANTONII [103]
3 years ago
12

Find the unit rate

Mathematics
1 answer:
Anna71 [15]3 years ago
3 0

Answer:

A.  $5

B.  $7

C.  $40

D.  $4

Step-by-step explanation:

To find the unit rate, you need to divide the cost by the amount.

A.  $25/5 = $5 for a movie ticket

B.  $35/5 = $7 for one yard

C.  $240/6 = $40 for a calculator

D.  $8/2 = $4 for a can of tuna

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Eric has $115 to spend on back to school clothes. So far, he has spent $90. Write an inequality to show how much more money Eric
Ede4ka [16]

Answer:

115 - 90 = 25

Step-by-step explanation:

115 - 90, which is equal to 25, is less than or equal to x!

3 0
2 years ago
Wayne Gretsky scored a Poisson mean six number of points per game. sixty percent of these were goals and forty percent were assi
BartSMP [9]

Answer:

a) The mean for the total revenue he earns per game is of 13.2K while the standard deviation is of 3.63K.

b) 0.05 = 5% probability that he has four goals and two assists in one game

Step-by-step explanation:

In hockey, a point is counted for each goal or assist of the player.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval. The standard deviation is the square root of the mean.

(a) Find the mean and standard deviation for the total revenue he earns per game.

60% of six are goals, which means that 60% of the time he earned 3K.

40% of six are goals, which means that 40% of the time he earned 1K.

The mean is:

\mu = 6*0.6*3 + 6*0.4*1 = 13.2

The standard deviation is:

\sigma = \sqrt{\mu} = \sqrt{13.2} = 3.63

The mean for the total revenue he earns per game is of 13.2K while the standard deviation is of 3.63K.

(b) What is the probability that he has four goals and two assists in one game

Goals and assists are independent of each other, which means that we find the probability P(A) of scoring four goals, the probability P(B) of getting two assists, and multiply them.

Probability of four goals:

60% of 6 are goals, which means that:

\mu = 6*0.6 = 3.6

The probability of scoring four goals is:

P(A) = P(X = 4) = \frac{e^{-3.6}*(3.6)^{4}}{(4)!} = 0.19122

Probability of two assists:

40% of 2 are assists, which means that:

\mu = 6*0.4 = 2.4

The probability of getting two assists is:

P(B) = P(X = 2) = \frac{e^{-2.4}*(2.4)^{2}}{(2)!} = 0.26127

Probability of four goals and two assists:

P(A \cap B) = P(A)*P(B) = 0.19122*0.26127 = 0.05

0.05 = 5% probability that he has four goals and two assists in one game

5 0
2 years ago
How do I show the relationship between the input and the output
alexgriva [62]

Answer:

Types of Relationships between the Input and Output

The scatter plot can be a useful tool in understanding the type of relationship that exist between the inputs (X’s) and the outputs (Y’s)

Step-by-step explanation:

1. No Relationship: The scatter plot can give an obvious suggestion if the inputs and outputs on the graph are not related. The points will be scattered throughout the graph with no particular pattern. For no relationship to exist, points have to be completely diffused. If some points are in concentration, then maybe a relationship does exist and our analysis has not been able to uncover it.

2. Linear and Non-Linear: A linear correlation exists when all the points are plotted close together. They form a distinct line. On the other hand points could be close together but they could form a relationship which has curves in it. The nature of the relationship has wide ranging implications.

3. Positive and Negative: A positive relationship between the inputs and the outputs is one wherein more of one input leads to more of an output. This is also known as a direct relationship.

On the other hand a negative relationship is one where more of one input leads to less of another output. This is also known as an inverse relationship.

4. Strong and Weak: The strength of the correlation is tested by how closely the data fits the shape. For instance if all the points are scattered very close together to form a very visible line then the relationship is strongly linear. On the other hand, if the relationship does not so obviously fit the shape then the relationship is weak.

I don't know if this was exactly what you were looking for; hope it is! :)

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3 years ago
Lesson Check (4.MD.C.7)
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The measure of Zx is 4
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The answer is y=-1x +11
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