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miss Akunina [59]
3 years ago
13

Kenneth Drew a scale drawing of an apartment the scale of the drawing was 2 meters:1 meter the living room is 6 m long in real l

ife how long is the living room in drawing
Mathematics
1 answer:
atroni [7]3 years ago
3 0

Answer:

3 meters

Step-by-step explanation:

Given the scale drawing :

2m : 1m

Length of living room in real life = 6 m long

2 meter = 1 meter

Real life = scale drawing

If length = 6 meter long ;

using cross multiplication :

2 meter = 1 meter

6 meter = x

2x = 6

x = 6/2

x = 3 meter

Length of living room in drawing = 3 meters

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nikklg [1K]

Answer:

22

Step-by-step explanation:

27-4+7-8=

23+7-8=

30-8=

22

3 0
3 years ago
What is the answer to 1/4 - (-1/6)​
Aloiza [94]

Answer:

5/12

Step-by-step explanation:

1/4 + 1/6 = (6+4)/24 = 10/24 = 5/12

why +1/6?

because: - (-) = +

4 0
3 years ago
4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
3 years ago
If you triple a number and add 11 you get 200 what is the number
Dafna1 [17]
You can set up a simple algebraic equivalent to find a number equivalent to 200 after being multiplied by 3 and added 11 to.

3x+11=200
3x=189
x=63

Had to edit! Realized what I had done wrong
8 0
3 years ago
Read 2 more answers
What is the equation of the function shown in the graph provided?<br><br> y= _ x + _
Mkey [24]

Answer:

y = -3x - 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from graph.</em>

x-intercept (-2, 0)

y-intercept (0, -6)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                  m=\frac{-6-0}{0+2}
  2. Subtract/Add:             m=\frac{-6}{2}
  3. Divide:                        m=-3

<u>Step 3: Redefine</u>

Slope <em>m</em> = -3

y-intercept <em>b</em> = -6

<u>Step 4: Write linear equation</u>

Slope-Intercept Form:   y = -3x - 6

7 0
3 years ago
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