What is an equation of the axis of symmetry for the parabola whose equation is y=2x^2 + 8x-1
1 answer:
Answer:
x = - 2
Step-by-step explanation:
The equation of the axis of symmetry is a vertical line with equation
x = c
where c is the value of the x- coordinate of the vertex
The x- coordinate of the vertex is
x = -
Given
y = 2x² + 8x - 1
with a = 2 and b = 8 , then
x = - = - 2
x = - 2 is the equation of the axis of symmetry
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Given:
• Upper Base of trapezoid = 8 cm
,• Lower base = 20 cm
,• Length of one leg (also height) = 5 cm
,• Length of other leg = 13 cm
Let's find the area of the trapezoid.
To find the area of the trapezoid, apply the formula:
Where:
A is the area
a is the length of upper base = 8 cm
b is the length of the lower base = 20 cm
h is the height = 5 cm
Plug in the values for a, b, and h to find the area, A:
Therefore, the area of the trapezoid is 70 cm^2