All categories

3 years ago

Suppose tanΘ = 3/5, and that Θ is in quadrant I. Find tan2Θ.

Mathematics

1 answer:

In-s [12.5K]3 years ago

3 0

Answer:

15/8

Step-by-step explanation:

tan 2θ = 2 tan θ / (1 − tan² θ)

tan 2θ = 2 (3/5) / (1 − (3/5)²)

tan 2θ = (6/5) / (1 − 9/25)

tan 2θ = (6/5) / (16/25)

tan 2θ = (6/5) × (25/16)

tan 2θ = 15/8

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$-4.9 x^{2} +12x+2.5=-4.9 x^{2} +14x \\ \\ 
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For Karl:
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