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3 years ago

Suppose tanΘ = 3/5, and that Θ is in quadrant I. Find tan2Θ.

Mathematics

1 answer:

In-s [12.5K]3 years ago

3 0

Answer:

15/8

Step-by-step explanation:

tan 2θ = 2 tan θ / (1 − tan² θ)

tan 2θ = 2 (3/5) / (1 − (3/5)²)

tan 2θ = (6/5) / (1 − 9/25)

tan 2θ = (6/5) / (16/25)

tan 2θ = (6/5) × (25/16)

tan 2θ = 15/8

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b) 2.56% probability that none of the offices are filled by members of the debate team

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the people are chosen is important, since the first person is the president, the second is the vice president and so on... So we use the permutations formula to solve this question.

Permutations formula:

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(a) What is the probability that all of the offices are filled by members of the debate team?

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4(president, vice president, secretary, and treasurer) offices from a set of 8(candidates of the members debate team).

$D = P_{(8,4)} = \frac{8!}{(8-4)!} = 1680$

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$T = P_{(15,4)} = \frac{15!}{(15-4)!} = 32760$

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5.13% probability that all of the offices are filled by members of the debate team

(b) What is the probability that none of the offices are filled by members of the debate team?

Desired outcomes:

4(president, vice president, secretary, and treasurer) offices from a set of 7(candidates who are not of the members debate team).

$D = P_{(7,4)} = \frac{7!}{(7-4)!} = 840$

Total outcomes:

4 offices from a set of 15 candidates.

$T = P_{(15,4)} = \frac{15!}{(15-4)!} = 32760$

Probability:

$P = \frac{D}{T} = \frac{840}{32760} = 0.0256$

2.56% probability that none of the offices are filled by members of the debate team

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