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Elis [28]
3 years ago
11

Problem #1 -Find the equation of the line with the given slope and containing the given point.

Mathematics
1 answer:
DaniilM [7]3 years ago
3 0
For 1)

\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ -7}}\quad ,&{{ 0}})\quad 
%   (c,d)

\end{array}
\\\quad \\\\ % slope  = m
slope = {{\boxed{ m}}}= \cfrac{rise}{run} \implies 
\implies -\cfrac{3}{5}
\\ \quad \\\\
% point-slope intercept
y-{{ y_1}}={{\boxed{ m}}}(x-{{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}

for 2)

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ -3}}\quad ,&{{ 17}})\quad 
%   (c,d)
&({{ -7}}\quad ,&{{ 37}})
\end{array}
\\\quad \\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}
\\ \quad \\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}

then change the y= part to f(x) = 

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Find a formula for the nth partial sum of the series and use it to find the series' sum if the series converges.
Arisa [49]

Answer: S_n=5(1-\dfrac{1}{n+1}) ; 5

Step-by-step explanation:

Given series : [\dfrac{5}{1\cdot2}]+[\dfrac{5}{2\cdot3}]+[\dfrac{5}{3\cdot4}]+....+[\dfrac{5}{n\cdot(n+1)}]

Sum of series = S_n=\sum^{\infty}_{1}\ [\dfrac{5}{n\cdot(n+1)}]=5[\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}]

Consider \dfrac{1}{n\cdot(n+1)}=\dfrac{n+1-n}{n(n+1)}

=\dfrac{1}{n}-\dfrac{1}{n+1}

⇒ S_n=5\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}=5\sum^{\infty}_{1}[\dfrac{1}{n}-\dfrac{1}{n+1}]

Put values of n= 1,2,3,4,5,.....n

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All terms get cancel but First and last terms left behind.

⇒ S_n=5(1-\dfrac{1}{n+1})

Formula for the nth partial sum of the series :

S_n=5(1-\dfrac{1}{n+1})

Also, \lim_{n \to \infty} S_n = 5(1-\dfrac{1}{n+1})

=5(1-\dfrac{1}{\infty})\\\\=5(1-0)=5

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3 years ago
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