I answered ALL your 15 problems. Sorry, I took long.
Please mark me brainliest if this helped you. That will help me a lot ...
I hope it helps!
Answer:segment YZ ≈ 19.4 inangle X ≈ 85.3°angle Z ≈ 26.7°Explanation:1) Given two side lenghts and one angle you can use sine law:
![\frac{sinA}{a} = \frac{sinB}{b} = \frac{sinC}{c}](https://tex.z-dn.net/?f=%20%5Cfrac%7BsinA%7D%7Ba%7D%20%3D%20%5Cfrac%7BsinB%7D%7Bb%7D%20%3D%20%5Cfrac%7BsinC%7D%7Bc%7D%20)
2) Using the sides with length 43 in and 40in, and the corresponding opposite angles, Z and 68°, that leads to:
![\frac{sinZ}{43} = \frac{sin68}{40}](https://tex.z-dn.net/?f=%20%5Cfrac%7BsinZ%7D%7B43%7D%20%3D%20%5Cfrac%7Bsin68%7D%7B40%7D%20)
From which you can clear sinZ and get:
sinZ = 43 × sin(68) / 40 = 0.9967
⇒ Z = arcsine(0.9967) ≈ 85.36°
3) The third angle can be determined using 85.36° + 68° + X = 180°
⇒ X = 180° - 85.36° - 68° = 26.64°.
4) Finally, you can apply the law of sine to obtain the last missing length:
![\frac{x}{sin(26.64)} = \frac{40}{sin(68)}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7Bsin%2826.64%29%7D%20%3D%20%5Cfrac%7B40%7D%7Bsin%2868%29%7D%20)
From which: x = 40 × sin(26.64°) / sin(68°) = 19.34 in
The answer, then is:
segment YZ ≈ 19.4 in
angle X ≈ 85.3°
angle Z ≈ 26.7°
A40=a1 +(40-1)r
in this case r is 3 beceause -2+3 will be 1 etc
a40=-2 +39*3
Answer:
3805kg
Step-by-step explanation:
2400 ≥ 2350
1460 ≥ 1455
2400 + 1460≥ 2350 + 1455 = 3805
The lower bound is 3805kg
B. If im right can i get brainlest? Never had 1 before.