6(-2.3x-5)+(4x+11) What is the answer? Thanks!

plssss help me this is due tomorrow morning

Veronika [31]

Find percent -> 2nd month.

4264*.25==1066 phone calls+=4264

==5330 for 2nd month.

for 2nd -> 3rd

6396==5330*x, solve algebraically to get .20 == 20% increase from 2nd month to 3rd month.

7 0

3 years ago

Fran has 7 sheets of paper for a coloring project. If she only uses 1/3 of a sheet of paper per drawing how many drawings can sh

notka56 [123]

Answer:

21 drawings

Step-by-step explanation:

So lets figure out how many drawings she can make per page. If she make a drawing using 1/3 of the page she can make 3 drawings per page. Now that we know she can make 3 drawings per padge, we can figure out how manyt drawings she can make by multiply the pages by drawings per padge. Let x be the drawings she can make.

7*3=x

Multiple 7*3

21=x

She can make 21 drawings

8 0

3 years ago

A 500 cm piece of wire with a radius of 0.2 cm has a resistance of 0.025 ohm. Find an equation that relates these variables.

kirza4 [7]

Answer:

Step-by-step explanation:

7 0

3 years ago

I'm confused ‍♀️ please help

disa [49]

It would be the second bubble 24/8. The answer to 24/8 is 3 so they saw 3 octopuses in the tank.

7 0

3 years ago

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A psychological study found that men who were distance runners lived, on average, five years longer than those who were not dist

poizon [28]

Answer:

1. There is not enough evidence to support the claim that men who were distance runners lived, on average, five years longer than those who were not distance runners.

2. The test statistic is t.

Step-by-step explanation:

The question is incomplete:

Test the claim that men who were distance runners lived, on average, five years longer than those who were not distance runners.
Which of the following is the test statistic for the appropriate test to determine if men who are distance runners live significantly longer, on average, than men who are not distance runners?

The test statistic is t, as this is a t-test for the difference of means.

The claim is that men who were distance runners lived, on average, five years longer than those who were not distance runners.

Then, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=5\\\\H_a:\mu_1-\mu_2> 5

The significance level is 0.05.

The sample 1, of size n1=50 has a mean of 84.2 and a standard deviation of 10.2.

The sample 1, of size n1=30 has a mean of 79.2 and a standard deviation of 6.8.

The difference between sample means is Md=5.

$M_d=M_1-M_2=84.2-79.2=5$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{10.2^2}{50}+\dfrac{6.8^2}{30}}\\\\\\s_{M_d}=\sqrt{2.081+1.541}=\sqrt{3.622}=1.903$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{5-5}{1.903}=\dfrac{0}{1.903}=0$

The degrees of freedom for this test are:

$df=n_1+n_2-1=50+30-2=78$

This test is a right-tailed test, with 78 degrees of freedom and t=0, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>0)=0.5$

As the P-value (0.5) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that men who were distance runners lived, on average, five years longer than those who were not distance runners.

6 0

3 years ago

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