Hello here is a solution :
a walking path BE in a park intersects intersects two sides of the park at their midpoints. You walk from point D to E, E to B,
from B to C, and back to point D. How many yards did you walk?
2 answers:
Answer:
Total distance covered = 436 yards
Step-by-step explanation:
Walking path BE joins the midpoints B and E of the sides AC and AD.
By midsegment theorem,
"Line joining midpoints of two sides of a triangle is parallel and measure half of the third side"
m(BE) =
CD = 2(BE)
CD = 2(74) = 128 yd
From starting point D,
DE = 107 yd
EB = 74 yd
BC =
= 127 yd
CD = 128 yd
Total walking distance = DE + EB + BC + CD
= 107 + 74 + 127 + 128
= 436 yd
Total distance covered = 436 yards
You might be interested in
Answer: -6<x<5
Step-by-step explanation:
Given
Length is 3 m more than three times the width
Suppose width is x
So, the length is 3x+3
The area of a rectangle is
Area=