All categories

3 years ago

14 - ( 9t - 2 ) < - t + 30 Anyone know multistep equations

Mathematics

1 answer:

ZanzabumX [31]3 years ago

3 0

Answer:

t > -7/4

Step-by-step explanation:

Step 1: Write out inequality

14 - (9t - 2) < -t + 30

Step 2: Distribute

14 - 9t + 2 < -t + 30

Step 3: Combine like terms

-9t + 16 < -t + 30

Step 4: Add 9t to both sides

16 < 8t + 30

Step 5: Subtract 30 on both sides

-14 < 8t

Step 6: Divide both sides by 8

-7/4 < t

Step 7: Rewrite

t > -7/4

You might be interested in

The formula for the area of a rhombus with diagonals of lengths c and

Irina18 [472]

Answer: part a.) c =2A/d

Part b.) d = 7

Part C The diagonals are each 8

Step-by-step explanation: part b:

35= 10d/2 70= 10d. 7 =d

Part c 32= 2c²

64 = c²

√64 = √c²

c = 8

7 0

3 years ago

Read 2 more answers

We have seen that isosceles triangles have two sides of equal length. The angles opposite these sides have the same measure. Use

Naddik [55]

Question has missing figure, the figure is in the attachment.

Answer:

The measure of ∠1 is 65°.

The measure of ∠2 is 65°.

The measure of ∠3 is 50°.

The measure of ∠4 is 115°.

The measure of ∠5 is 65°.

Step-by-step explanation:

Given,

We have an isosceles triangle which we can named it as ΔABC.

In which Length of AB is equal to length of BC.

And also m∠B is equal to m∠C.

ext.m∠C= 115°(Here ext. stands for exterior)

We have to find the measure of angles angles 1 through 5.

Solution,

For ∠1.

∠1 and ext.∠C makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

$\angle1+ext.\angle C=180\°$

On putting the values, we get;

$\angle 1+115\°=180\°\\\\\angle1=180\[tex]\therefore m\angle2=65\°$ -115\°=65\°[/tex]

Thus the measure of ∠1 is 65°.

For ∠2.

Since the given triangle is an isosceles triangle.

So, $m\angle1=m\angle2$

Thus the measure of ∠2 is 65°.

For ∠3.

Here ∠1, ∠2 and ∠3 are the three angles of the triangle.

So we use the angle sum property of triangle, which states that;

"The sum of all the angles of a triangle is equal to 180°".

$\therefore \angle1+\angle2+\angle3=180\°$

Now we put the values and get;

$65\°+65\°+\angle3=180\°\\\\130\°+\angle3=180\°\\\\\angle3=180\°-130\°=50\°$

Thus the measure of ∠3 is 50°.

For ∠4.

∠4 and ∠2 makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

$\angle2 +\angle 4 =180\°$

Substituting the values of of angle 2 to find angle 4 we get;

$65\°+ \angle 4 = 180\°\\\\ \angle 4 = 180\°-65\°\\\\\angle 4= 115\°$

Thus the measure of ∠4 is 115°.

For ∠5.

∠4 and ∠5 makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

$\angle4 +\angle 5 =180\°$

Substituting the values of of angle 4 to find angle 5 we get;

$115\°+ \angle 5 = 180\°\\\\ \angle 5 = 180\°-115\°\\\\\angle 5= 65\°$

Thus the measure of ∠5 is 65°.

Hence:

The measure of ∠1 is 65°.

The measure of ∠2 is 65°.

The measure of ∠3 is 50°.

The measure of ∠4 is 115°.

The measure of ∠5 is 65°.

6 0

3 years ago

6(y+1.5)=18 what does y equals?

leva [86]

Answer:

Step-by-step explanation:

6y+9=18

6y=2

y=1/3

3 0

3 years ago

Read 2 more answers

The measure of ∠1 = 188 172 94

yanalaym [24]

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

There is a cyclic quadrilateral.

As we know that "Sum of opposite angles in a cyclic quadrilateral is supplementary.":

so, it becomes,

$86^\circ+\angle 1=180^\circ\\\\\angle 1=180^\circ-86^\circ\\\\\angle 1=94^\circ$

Hence, the measure of ∠1 = 94°

Therefore, Third option is correct.

4 0

3 years ago

Help Determine which equation is parallel to line jk and which is perpendicular to line jk.

alukav5142 [94]

Answer:

5x + 3y = 13 parallel.

6x - 10y = 7 perpendicular.

Step-by-step explanation:

Two lines with slopes $m_1$ and $m_2$ are parallel when $m_1=m_2$ and are perpendicular when $m_1*m_2=-1$

Now determine the slope of all the lines

The line jk passes through the points

(-5,5) and (1,-5) so its slope is

$\frac{-5-5}{1-(-5)}=\frac{-10}{6}=-\frac{5}{3}$

To determine the slope of the lines in the blue rectangles, isolate y from each one and the coefficient of x is the slope

5x-3y = 8 ------> y = (5/3)x + 8/3 ------> slope 5/3

Neither parallel nor perpendicular.

6x+10y = 11 ------> y = (-6/10)x + 11/10 = (-3/5)x + 11/10 ------> slope -3/5

Neither parallel nor perpendicular.

5x + 3y = 13 ------> y = (-5/3)x + 13/3 ------> slope -5/3

This line is parallel

6x - 10y = 7 ------> y = (6/10)x - 7/10 = (3/5)x -7/10 ------> slope 3/5

Since (-5/3)(3/5) = -1 this line is perpendicular.

8 0

3 years ago