The car will travel 387 ft in 5.00 s.
No. of kilometres = 5.00 s × (1 min/60 s) × (1 h/60 min) × (85.0 km/h) = 0.1181 km
No of feet = 0.1181 km × (1 mi/1.609 km) × (5280 ft/1 mi) = 387 ft
Answer:
Explanation:
At the cathode
In case of molten AgI
Silver will be collected
In case of molten LiI
lithium will be collected
in case of aqueous LiI,
hydrogen gas will be collected as reduction potential of H⁺ is more than Li⁺
in case of aqueous AgI,
Silver will be obtained at cathode because reduction potential of silver is more than H⁺
At the Anode
In case of molten NaBr
Bromine will be collected
In case of molten NaF
Fluorine will be collected
in case of aqueous NaBr ,
Bromine will be collected as reduction potential of Br⁻ is less than O⁻²
in case of aqueous NaF ,
oxygen will be obtained because reduction potential of F⁻ is more than O⁻² .
Really good question i hope to see the answer to
The mass of aluminium foil is calculated as follows
mass = density x volume
density = 2.70 g/cm^3
volume 54 cm^3
mass of aluminium foil is therefore = 2.70 g/cm^3 x 54 cm^3 =145.8 grams
cm^3 cancel out each other
False .... A neutral atom needs the same number of protons and electrons