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rusak2 [61]
3 years ago
5

Helppp solve the equation algebraically

Mathematics
1 answer:
katen-ka-za [31]3 years ago
4 0

Answer:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

( 3 , − 1 )

Equation Form:

x = 3 ,  y = − 1

Step-by-step explanation:

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You need to do cross multiplication
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2. Find the compound interest on Rs.25, 000 after 2 years compounded
Allushta [10]

Answer:25,000 in 2 years at annual compound interest, if the rates for the successive years be 4% and 5% per annum respectively is: (1) Rs. 30,000 (2) Rs. 26,800 fa) Rs.

A=P[1+  

100

r

​  

]  

n

 

⇒  A=Rs.25,000×(  

100

106

​  

)  

3

 

⇒  25,000×  

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​  

×  

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​  

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⇒  A=Rs.29,775.40

⇒  CI=A−P

⇒  Rs.29,775.40−Rs.25,000

∴   CompoundInterest=Rs.4775.40.

6 0
3 years ago
would set a new school record? A number line going from 515 to 521. An open circle is at 518. Everything to the left of the circ
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Answer:

C

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Rearrange the fractions in order from least to greatest. Show your work
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Sorry but, I can't help you with all of them. Here is a and how would you show your work?

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Step-by-step explanation:

8 0
3 years ago
What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth
EleoNora [17]
Check the picture below.

so... you can pretty much see how long RS and QT are, you can just count the units off the grid.

now, let's find QR's length

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&Q&(~ 8 &,& 8~) 
%  (c,d)
&R&(~ 14 &,& 16~)
\end{array}~~ 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
QR=\sqrt{(14-8)^2+(16-8)^2}\implies QR=\sqrt{6^2+8^2}
\\\\\\
QR=\sqrt{36+64}\implies QR=\sqrt{100}\implies QR=10

and let's also find the length for ST

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&S&(~ 20 &,& 16~) 
%  (c,d)
&T&(~ 22 &,& 8~)
\end{array}~ 
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
ST=\sqrt{(22-20)^2+(8-16)^2}\implies ST=\sqrt{2^2+(-8)^2}
\\\\\\
ST=\sqrt{4+64}\implies ST=\sqrt{68}\implies ST=\sqrt{4\cdot 17}
\\\\\\
ST=\sqrt{2^2\cdot 17}\implies ST=2\sqrt{17}

so, add the lengths of all sides, and that's the perimeter of the trapezoid.

8 0
4 years ago
Read 2 more answers
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