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3 years ago

Pls help look at picture

Mathematics

1 answer:

Brums [2.3K]3 years ago

5 0

Answer: C

Step-by-step explanation:

Looking at the triangle, we see that the angles are the same. This tells us the triangle is an isosceles triangle. That means the two adjacent sides are equal to each other.

4x+23=10x-1 [subtract both sides by 4x]

23=6x-1 [add both sides by 1]

24=6x [divide both sides by 6]

x=4

Now, we know that x=4.

You might be interested in

what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible

zheka24 [161]

The quotient when $\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$ in simplified form is $\frac{-(x+1)}{(x-1)(x+3)}$

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

$\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$

$=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}$

The quotient when $\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$ in simplified form is $\frac{-(x+1)}{(x-1)(x+3)}$

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0

2 years ago

NarStor, a computer disk drive manufacturer, claims that the median time until failure for their hard drives is more than 14,400

Ne4ueva [31]

Answer:

The test statistics is $t = -1.727$

Step-by-step explanation:

From the question we are told that

The data given is

330 620 1870 2410 4620 6396 7822 81028309 12882 14419 16092 18384 20916 23812 25814

The population mean is $\mu = 14400$

The sample size is n = 16

The null hypothesis is $\mu \le 14400$

The alternative hypothesis is $H_a : \mu > 14400$

The sample mean is mathematically evaluated as

$\= x = \frac{\sum x_i}{n}$

$\= x = \frac{330+ 620+ 1870 +2410+ 4620+ 6396+ 7822+ 8102+8309+ 12882+ 14419+ 16092+ 18384 +20916+ 23812+ 25814 }{16}$

=> $\= x = 10799.9$

The standard deviation is mathematically represented as

$\sigma =\sqrt{\frac{ \sum (x_i - \=x)^2}{n}}$

$\sigma =\sqrt{\frac{(330- 10799.9)^2 + (620- 10799.9)^2+ (1870- 10799.9)^2 +(2410- 10799.9)^2 + (4620- 10799.9)^2 +(6396- 10799.9)^2 +(7822- 10799.9)^2 }{16}} \ ..$

$..\sqrt{ \frac{(8102 - 10799.9)^2 +(8309 - 10799.9)^2 + (12882 - 10799.9)^2 + (14419 - 10799.9)^2 + (16092 - 10799.9)^2 + (18384 - 10799.9)^2 +(20916 - 10799.9)^2 }{16}} \ ...$

$\ ... \sqrt{\frac{(23812 - 10799.9)^2 +(25814 - 10799.9)^2 }{16}}$

=> $\sigma = 8340$

Generally the test statistic is mathematically represented as

$t = \frac{10799.9- 14400}{ \frac{8340}{\sqrt{16} } }$

$t = -1.727$

From the z-table the p-value is

$p-value = P(Z > t) = P(Z > -1.727) = 0.95792$

From the values obtained we see that

$p-value > \alpha$ so we fail to reject the null hypothesis

Which implies that the claim of the NarStor is wrong

5 0

3 years ago

Koran is spending $12 on games and rides at another carnival, where a game costs $0.25 and a ride costs $1.

Vlad [161]

Answer:

$0.25x+y=12$

Step-by-step explanation:

Let

y ----> the number of rides

x ---> the number of games

we know that

The number of rides multiplied by $1 plus the number of games multiplied by $0.25 must be equal to $12 (the dollar amount Koran is spending)

The equation that represent this situation is

$0.25x+y=12$

5 0

3 years ago

The difference of two numbers is 40. Their sum is 66. Find the numbers.

Margaret [11]

First of all, x>y
x-y=40
and
x+y=66
add them equations together to eliminate

x-y=40
<u>x+y=66 +</u>
2x+0y=106

2x=106
divide by 2
x=53

sub back
x-y=40
53-y=40
minus 53 both sides
-y=-13
y=13

the numbers are 53 and 13

8 0

3 years ago

Read 2 more answers

Yuki888 [10]

Answer:

Radius: 8.5 inches

Area ≈ 226.98

Circumference ≈ 53.42

Step-by-step explanation:

2πr = formula for circumference of a circle

πr² = formula for area of a circle

radius of a circle = (1/2)d

3 0

2 years ago

Pls help look at picture​

Pls help look at picture