Step One
Calculate the number of feet traveled in 1 rotation.
Formula
C = π*d
P = 3.14
d = 9 inches = 9/12 feet = 3/4 of a foot.
C = 3.14 * 3/4 = 2.355 So that means that every time the tire turns around 1 complete turn, the distance traveled on the ground is 2.355 feet.
Step Two
Figure out the number of revolutions.
1 revolution = 2.355 feet
x revolutions = 300 feet.
1/x = 2.355/ 300 Cross multiply
2.355 feet * x = 1 rev * 300 feet
2.355 x = 300 rev Divide by 2.355
x = 300 / 2.355
x = 127.39 revolutions. <<<< Answer
7n-4=31
7n=31-4
7n=27
n=27/7
:n=3
It’s equation and it’s really easy to solve
Answer:
see below
Step-by-step explanation:
72pi cubic inches
1/3 pi r ^2 * h = 72 pi
1/3 r^2 h = 72
You can theoretically find infinite answers to this and get enough points for the semester where you don't have to do work anymore. I will list a couple more possible answers below
r = radius, h = height
r = 2, h = 54
r = 3, h = 24
r = 4, h = 27/2
r = √(1/pi), h = 72pi
Let x be the 1st odd number, and x+2 the second odd consecutive number:
(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1
x² + 2x = 12x +12 - 1
And x² - 10x - 11=0
Solve this quadratic expression:
x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2
x' = [10 + √144]/2 and x" = [10 - √64]/2
x' = (10+12)/2 and x" = (10-12)/2
x = 11 and x = -1
We have 2 solutions that satisfy the problem:
1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity
6x^4-2x^3+26x^2+x+14 would be your anwser.
