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3 years ago

15) What is the difference between a rhombus and a square?

Mathematics

1 answer:

PIT_PIT [208]3 years ago

4 0

Answer:

C) The angles in a square measure 90 degrees. The rhombus has obtuse and

acute angles.

Step-by-step explanation:

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An 18 ft. tree casts a 15 ft. long shadow as shown in the following figure. Which of the following is the angle formed by the su

BabaBlast [244]

Answer:

The angle is 50.2°.

Step-by-step explanation:

The tree and its shadow from a right triangle with the tree being the perpendicular and the shadow being the base as shown in the figure attached.

Therefore the angle θ formed by the sun's rays and the ground is:

$\theta = tan^-1(\frac{18}{15} )=\boxed{50.2^o}$

8 0

3 years ago

Please I need help on these two

KIM [24]

Question 1: C, x < -8 <---

Question 2: A, n>= -4

5 0

3 years ago

On a town map, each unit of the coordinate plane represents 1 mile. Three branches of a bank are located at A(−3, 1), B(3, 3), a

Andrei [34K]

Answer:

The minimum total distance the employee may have driven before getting stuck in traffic is 8.3 miles

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of the distance between to points $(x_{1},y_{1})$

and $(x_{2},y_{2})$ i s $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

- So at first we will find the distance between the three points

∵ A = (-3 , 1) , B = (3 , 3) , C = (3 , -1)

- By using the rule of distance

∴ $AB=\sqrt{(3--3)^{2}+(3-1)^{2}}=\sqrt{36+4}=\sqrt{40}=6.325$

∴ $BC=\sqrt{(3-3)^{2}+(-1-3)^{2}}=\sqrt{0+16}=4$

∴ $AC=\sqrt{(3--3)^{2}+(-1-1)^{2}}=\sqrt{36+4}=\sqrt{40}=6.325$

∵ Each unit coordinate plane represents 1 mile

∵ AB = 6.3 units

∴ The distance between branches A and B = 6.325 miles

∵ BC = 4 units

∴ The distance between branches B and C = 4 miles

∵ AC = 6.3 units

∴ The distance between branches A and C = 6.325 miles

- A bank employee drives from Branch A to Branch B and then

drives halfway to Branch C before getting stuck in traffic

∵ The distance from branch A to branch B is 6.325 miles

∵ The distance from branch B to branch C is 4 miles

∵ The half way from branch B to branch C = 1/2 × 4 = 2 miles

∴ The distance the employee may have driven before getting

stuck in traffic = 6.325 + 2 = 8.325 miles

∴ The minimum total distance the employee may have driven

before getting stuck in traffic is 8.3 miles

8 0

3 years ago

Please someone who to help me to solve this question.

Lorico [155]

First you have make the 2 and a half into 5/2. Then you have to find a common denominator of the two fractions, which would be 8. So the 7/8 you dont need to do anything to but the 5/2 you do... so multiply both the top and the bottom by 4 so you can get 8 on the bottom. that would be 20/8. now you can add them. so 7/8 + 20/8 = 27/8

6 0

3 years ago

Read 2 more answers

Solve for x, Show your work: 1/2 (16 - x) = -12 (x + 7)

soldi70 [24.7K]

You have to get rid of 1/2 by multiplying it by its recriprocal which is like this:
1) 1/2 x 2/1 which equals to zero and you do the same to the other side.
2) -12 x 2/1 = -24x then multiply-24x with 7 which equals -168.
16-x= -24x -168
3) subtract 16 to the other side and subtract 24x with x
23x= -184
4) divide by 23 to isolate x and you get -8
5) x=-8

6 0

3 years ago

Read 2 more answers