Equation of line passing through given points :
Let's proceed with two point form ~
Assume :
So, the equation of required line is : y = 3 ~
Am going to presume you want it solved.
Please pardon my presumption
7 - (2/3)x < x - 8, Take all the x to one side of the inequality
-(2/3)x-x < - 8 -7
-(5/3)x < - 15 Divide both sides by -5/3 and inequality sign changes
x > (-15)/(-5/3)
x > 15 * 3/5 . 5 into 15 is 3.
x > 3*3
x > 9
Radius, r = 3
The equation of a sphere entered at the origin in cartesian coordinates is
x^2 + y^2 + z^2 = r^2
That in spherical coordinates is:
x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)
where you can make u = r cos(phi) to obtain the parametrical equations
x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u
where theta goes from 0 to 2π and u goes from -r to r.
In our case r = 3, so the parametrical equations are:
Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
