Let

be a probability that i-th light fails, where i=1,2,3. Then,

is the probability that i-th light remain bright.
<span>If the lights fail independently of each other, the probability that a string of lights will remain bright for two years is:
</span>

.
Probably infinite depending on if u mean how many factors it has
F(59)=3x-2
f(59)=3(59)-2
f(59)=177-2
f(59)=175
Answer:
6. D.
7. F.
8. A.
9. B.
10. C.
Step-by-step explanation:
6. 9 + (12 - 10)
12 - 10 = 2
9 + 2 = 11
7. (20 - 15) x 2
20 - 15 = 5
5 x 2 = 10
8. 10 ÷ 5 + 7
10 ÷ 5 = 2
2 + 7 = 9
9. 6 + 2 x 3
2 x 3 = 6
6 + 6 = 12
10. (2 x 4) + 8
2 x 4 = 8
8 + 8 = 16
Let me know if this helps!
Answer:
g = 7/2
Step-by-step explanation:
-5 + 7g = 3g + 9
~Add 5 to both sides
7g = 3g + 14
~Subtract 3 to both sides
4g = 14
~Divide 4 to both sides
g = 14/4 or g = 7/2
Best of Luck!