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OverLord2011 [107]
3 years ago
10

Any one help me with this plsss and ni links plss!!

Mathematics
1 answer:
Bas_tet [7]3 years ago
4 0

Answer:

6. D.

7.  F.

8. A.

9. B.

10. C.

Step-by-step explanation:

6.     9 + (12 - 10)

       12 - 10 = 2

        9 + 2 = 11

7.      (20 - 15) x 2

        20 - 15 = 5

         5 x 2 = 10

8.      10 ÷ 5 + 7

         10 ÷ 5 = 2

          2 + 7 = 9

9.        6 + 2 x 3

           2 x 3 = 6

           6 + 6 = 12

10.        (2 x 4) + 8

             2 x 4 = 8

             8 + 8 = 16

Let me know if this helps!

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According to a study done by a university​ student, the probability a randomly selected individual will not cover his or her mou
Sergio [31]

Using the binomial distribution, it is found that:

a) There is a 0.1618 = 16.18% probability that among 18 randomly observed individuals exactly 6 do not cover their mouth when​ sneezing.

b) There is a 0.104 = 10.4% probability that among 18 randomly observed individuals fewer than 3 do not cover their mouth when​ sneezing.

c) 9 is more than 2.5 standard deviations below the mean, hence it would not be surprising if fewer than half covered their mouth when​ sneezing.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

The values of the parameters are given as follows:

n = 18, p = 0.267.

Item a:

The probability is P(X = 6), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{18,6}.(0.267)^{6}.(0.733)^{12} = 0.1618

There is a 0.1618 = 16.18% probability that among 18 randomly observed individuals exactly 6 do not cover their mouth when​ sneezing.

Item b:

The probability is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2).

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{18,0}.(0.267)^{0}.(0.733)^{18} = 0.0037

P(X = 1) = C_{18,1}.(0.267)^{1}.(0.733)^{17} = 0.0245

P(X = 2) = C_{18,2}.(0.267)^{2}.(0.733)^{16} = 0.0758

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0037 + 0.0245 + 0.0758 = 0.104.

There is a 0.104 = 10.4% probability that among 18 randomly observed individuals fewer than 3 do not cover their mouth when​ sneezing.

item c:

We have to look at the mean and the standard deviation, given, respectively, by:

  • E(X) = np = 18 x 0.267 = 4.81.
  • \sqrt{V(X)} = \sqrt{18(0.267)(0.733)} = 1.88

9 is more than 2.5 standard deviations below the mean, hence it would not be surprising if fewer than half covered their mouth when​ sneezing.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

6 0
2 years ago
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