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2 years ago

How many terms are there in the expression 2x - 3y + 8?

Mathematics

1 answer:

kenny6666 [7]2 years ago

3 0

Answer:

Three. 2x, -3y, and 8.

Step-by-step explanation:

For every constant or variable, there is a term.

In this expression, there are two variables (x and y) and there is a constant (8).

Hence, there are three terms.

Hope this helped!

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A commuter airline makes lattes in the galley and sells them to passengers. A regular latte contains a shot of espresso, 1 cup o

Alik [6]

Answer:

To maximize profit, the amount of each type of coffees made are;

The number of regular latte made = 52 cups

The number of low-fat latte made = 48 cups

Step-by-step explanation:

The given parameters are;

The number of espresso in a regular latte = 1 shot

The number of cups of 2% milk in regular latte = 1 cup

The amount of whipped cream in a regular latte = 0.5 cup

The number of cups of skim milk in the low-fat latte = 1.25 cup

The number of espresso in a low-fat latte = 1 shot

The amount of whipped cream in a low-fat latte = 0 cup

The number of cups of espresso in the journey = 100 shots

The number of cups of skim milk in the journey = 60 cups

The number of cups of 2% milk in the journey = 60 cups

The amount of profit the airline makes on each regular latte = $1.58

The amount of profit the airline makes on each low-fat latte = $1.65

Let 'x' represent the number regular lattes made and let 'y' represent the number low-fat lattes made, we have;

x ≤ 30/0.5 = 60

x ≤ 60

y ≤ 60

y ≤ 60/1.25 = 48

∴ y ≤ 48

x + y ≤ 100

Therefore, the given that more profit is made from the sale of low-fat latte than for regular latte, the maximum number of low-fat latte should be made

Therefore, the number of low-fat latte made, y = 48

Therefore, the number of regular latte made, x ≤ 100 - 48 = 52

For maximum profit, the maximum number of low-fat latte, 'x', should be made

Therefore, x = 52

The ideal mix of regular and low-fat lattes to maximize profit is 52 cups of regular latte and 48 cups of low-fat latte

5 0

3 years ago

Suppose that in a senior college class of 500 students itis found that 210 smoke, 258 drink alcoholic beverages, 216 eatbetween

Katarina [22]

Answer:

a)Smoke but doesn't drink alcoholic beverages

P=0.176 or 17.6%

b)eats between meals and drinks alcoholic beverages but doesn't smoke

P=0.062 or 6.2%

c.) neither smokes nor eats between meals

P=0.342 or 34.2%

Step-by-step explanation:

Using a Venn diagram with three circles, one for each bad health habit. Let us $a$ for the students that only smoke, $b$ for only drink alcoholic beverages, and $c$ for only eat between meals. Following this logic, $d$ represents smoke and drink alcoholic beverages but not eat between meals, $e$ drink alcoholic beverages and eat between meals but not smoke, $f$ eat between meals and smoke but not drink alcoholic beverages. Finally $g$ for having all the three, this means $g=52$ .

To find $f$ , subtract 52 (the three problems) from 97 because this last number represents all the students that smoke and eat between meals, including the students that have the three bad habits. The same goes for 'd' and 'e'.

$f=97-52=45$

$e=83-52=31$

$d=122-52=70$

To find $a$ , subtract $e$ , $f$ , and $g$ from the total of smokers. This is because $e$ , $f$ , and $g$ represent smoke and at least another bad habit and $a$ represents only smoking.

$a=210-d-f-g=210-70-45-52=43$