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3 years ago

In the right triangle A=30 and BC=4 how long is AB? HELP ASAP!!!!!

Mathematics

2 answers:

kicyunya [14]3 years ago

5 0

Answer:

Step-by-step explanation:

using the formula,

sin A = opp/hyp

where opp = CB = 4

hyp = AB = x

and A = 30

sin 30 = 4/x

0.5 = 4/x

x = 4/ 0.5 = 8

Andre45 [30]3 years ago

3 0

sin(30°) = 4/x. Multiply both sides by x.

x * sin(30°) = 4. Divide each side by sin(30°).

x = 4/sin(30°). Solve for x.

x = 8.

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Siddarth is putting baseball cards into a book that has 100 pages. Each page holds 9 cards. If Josh has 828 baseball cards, how

Mice21 [21]

Answer: 8

Step-by-step explanation: You would have to divide 828/9. The answer would be 92. You would then subtract this number from 100 pages to get your answer.

7 0

3 years ago

What is f(3)??????????

AURORKA [14]

<h3><u>Explanation</u></h3>

Meaning of f(a)

f(a) means the value of f(x) is ... when x = a. That means if we substitute x = 3, we would get f(3).

f(3) also means the value of f(x) is ... when x = 3.

f(x) can also be defined as y // f(x) = y

Find f(3) by graph.

You can find the value of f(x) at specific domain from the graph by looking at x = 3 then look up to where the point or where the graph passes. From the graph, when x = 3 as we look up and the graph passes y-coordinate at 1.

Therefore we can say that when x = 3, y = 1.

<h3><u>Answer</u></h3>

f(3) = 1

8 0

3 years ago

Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 2t, 1 + 6t, 1 + 14t . Find the points at which their p

GuDViN [60]

Answer:

A) points at which paths intersect : (1,1,1) ; (2,4,8)

B) DNE

Step-by-step explanation:

A) To find the points in which the particle paths intersect, it is necessary to find the values of t for which the three components of both vectors are equal:

$t_1=1+2t_2\\\\t_1^2=1+6t_2\\\\t_1^3=1+14t_2$

you replace t1 from the first equation in the second equation:

$(1+2t_2)^2=1+6t_2\\\\1+4t_2+4t_2^2=1+6t_2\\\\4t_2^2-2t_2=0\\\\t_2(2t_2-1)=0\\\\t_2=0\\\\t_2=\frac{1}{2}$

Then, for t2 = 0 and t2=1/2 you obtain for t1:

$t_1=1+2(0)=1\\\\t_1=1+2(\frac{1}{2})=2$

Hence, for t1=1 and t2=0 the paths intersect. Furthermore, for t1=2 and t2=1/2 the paths also intersect.

The points at which the paths intersect are:

$r_1(1)=(1,1,1)=r_2(0)=(1,1,1)\\\\r_1(2)=(2,4,8)=r_2(\frac{1}{2})=(2,4,8)$

B) You have the following two trajectories of two independent particles:

$r_1(t)=(t,t^2,t^3)\\\\r_2(t)=(1+2t,1+6t,1+14t)$

To find the time in which the particles collide, it is necessary that both particles are in the same position on the same time. That is, each component of the vectors must coincide:

$t=1+2t\\\\t^2=1+6t\\\\t^3=1+14t$

From the first equation you have:

$t=1+2t\\\\t=-1$

This values does not have a physical meaning, then, the particle do not collide

answer: DNE

5 0

3 years ago

The area of a circular pool cover is 314 square feet. Write and solve an equation to find the diameter of the pool cover. Use 3.

nikitadnepr [17]

The diameter of the pool cover in one hundred feet

4 0

3 years ago

Given a+b=7 and a–b=3, find:<br><br> 2^a*2^b

seropon [69]

Answer:

128

Step-by-step explanation:

5+2=7

5-2=3

2^5=32

2^2=4

32*4=128

Hope this helps:)

7 0

3 years ago