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3 years ago

In the right triangle A=30 and BC=4 how long is AB? HELP ASAP!!!!!

Mathematics

2 answers:

kicyunya [14]3 years ago

5 0

Answer:

Step-by-step explanation:

using the formula,

sin A = opp/hyp

where opp = CB = 4

hyp = AB = x

and A = 30

sin 30 = 4/x

0.5 = 4/x

x = 4/ 0.5 = 8

Andre45 [30]3 years ago

3 0

sin(30°) = 4/x. Multiply both sides by x.

x * sin(30°) = 4. Divide each side by sin(30°).

x = 4/sin(30°). Solve for x.

x = 8.

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$\text{BR}=\sqrt{(7-6)^2+(3-4)^2}=\sqrt{1^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}\\\\\text{RA}=\sqrt{(6-3)^2+(4-3)^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{AD}=\sqrt{(3-6)^2+(3-2)^2}=\sqrt{(-3)^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{DB}=\sqrt{(6-7)^2+(2-3)^2}=\sqrt{(-1)^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}$

The lengths of the sides of KELY are:

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