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zzz [600]
3 years ago
7

274,635 rounded to the nearest thousands

Mathematics
1 answer:
Firlakuza [10]3 years ago
6 0

275000 is your answer

hope it help

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Which solid shapes have both flat and curved surfaces?
RSB [31]
I think it may be a cylinder
6 0
3 years ago
The mean of four numbers is 70. When a fifth number is included, the mean of the five numbers is 80. What is the fifth number?
Yakvenalex [24]
<h3>Answer: 120</h3>

=============================================

Explanation:

S = sum of the first four values

S/4 = 70 since we divide the sum by 4 to get the mean of the first four values

S = 280 is the result after multiplying both sides by 4

Let x be the fifth unknown value. Adding it onto S leads to S+x = 280+x. This represents the sum of all five values.

Dividing that sum 280+x over 5 leads to the new mean 80, which leads to...

----------

(280+x)/5 = 80

280+x = 5*80

x+280 = 400

x = 400-280

x = 120

The fifth number is 120

3 0
3 years ago
I really need some help. I need to find the inverse of this equation in the picture below. Thanks!
serg [7]

Answer:

y=81x^4+648x^3+1944x^2+2592x+1289

Step-by-step explanation:

1. Interchange x and y.

  • y=\frac{\sqrt[4]{x+7}}{3}-2
  • x=\frac{\sqrt[4]{y+7}}{3}-2

2. Then solve x=\frac{\sqrt[4]{y+7}}{3}-2 for y.

3. y=81x^4+648x^3+1944x^2+2592x+1289

I hope this helps.

4 0
3 years ago
A square has sides that are 80 ft long. Which equations can be used to calculate d the length of a diagonal of the square in fee
LenKa [72]
Notice the picture below

just use the pythagorean theorem to ge the diagonal

\bf c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}

7 0
3 years ago
Use the functions h(x) = 2x − 5 and t(x) = 6x + 4 to complete the function operations listed below.
Anika [276]
For this case we have the following functions:
 h (x) = 2x - 5
 t (x) = 6x + 4

 Part A: (h + t) (x)
 (h + t) (x) = h (x) + t (x)
 (h + t) (x) = (2x - 5) + (6x + 4)
 (h + t) (x) = 8x - 1

 Part B: (h ⋅ t) (x)
 (h ⋅ t) (x) = h (x) * t (x)
 (h ⋅ t) (x) = (2x - 5) * (6x + 4)
 (h ⋅ t) (x) = 12x ^ 2 + 8x - 30x - 20
 (h ⋅ t) (x) = 12x ^ 2 - 22x - 20

 Part C: h [t (x)]
 h [t (x)] = 2 (6x + 4) - 5
 h [t (x)] = 12x + 8 - 5
 h [t (x)] = 12x + 3
6 0
3 years ago
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