Arithmetic sequence: a_n=a_1+(n-1)d where: d = common difference between terms; n = term; a_1 = first term of sequence a_n = 3+(n-1)4 = 3+(4n-4) = 4n-1 Therefore, a_50 = 4(50)-1 = 200 - 1 = 199
Answer:
It is not greater than 1/2
Step-by-step explanation:
11/12-8/9 = 1/36
The equation in this problem is <span>f(x)=x^4−x^3−7x^ 2+x+6.
The complete factored form of this eqaution is F(x)=(x-1)(x-3)(x+1)(x+2)
-I hope this is the answer you are looking for, feel free to post your questions here on brainly in the future.</span>
Good job u got the answer right
Hello:
<span>4 números inteiros consecutivos: n , (n+1) , (n+2) , (n+3)
</span><span>A soma de 4 números inteiros consecutivos é 326 :
</span>n +(n+1) +(n+2) +(n+3) = 326
4n +6 =326
4n =320
n = 80
segundo número : 81
