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mash [69]
3 years ago
14

I need help does anybody knows the answer

Biology
1 answer:
Marat540 [252]3 years ago
8 0
C i think





let me know if i was right :)
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An autosomal recessive disease has an incidence of 1/10,000. What is the approximate frequency of heterozygote carriers for this
goblinko [34]

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Option B

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Given

Number of incidences or frequency of an autosomal recessive disease = \frac{1}{10000}

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p+q=1

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p = 1-q\\p = 1-\frac{1}{100}\\p = \frac{99}{100}

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As per second equation of Hardy Weinberg's -

p^{2} + q^{2} + 2pq=1

Substituting the given values in above equation, we get -

\frac{9801}{10000} + \frac{1}{100} + 2pq=1\\2pq = 1-(\frac{9801}{10000} + \frac{1}{100})\\2pq = 0.99%\\OR[tex]2pq=1%

2pq = \frac{1}{100}

Hence, option B is correct.

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