Hope this helps X divided by 2 + 7 sorry I could not find a symbol for division
The attached triangles ABC and DEF are similar by SSS
<h3>Similar triangles</h3>
Triangles may be similar, congruent or not; this depends on the relationship between both triangles
<h3>
Equivalent ratio</h3>
For two or more triangles to be similar, then the corresponding sides of the triangles must have an equivalent ratio.
Take for instance, the attached triangle.
The triangles are similar, and the equivalent ratio (k) is calculated as follows:
Each quotient would result in 0.5.
So, we have:
This means that, the triangles are similar by SSS
Read more about similar triangles at:
brainly.com/question/14285697
Answer:
A, and D
Step-by-step explanation:
A works because when you multiply like bases, you add exponents, so we have...
5^7*5^-4 = 5^(7+(-4)) = 5^(7 -4) = 5^3
B doesn't work because when you divide like bases, you subtract the exponent of the denominator from the exponent of the denominator...
5^12/5^4 = 5^(12 - 4) = 5^8
C doesn't work because there is addition.
5 + 5² = 5 + 25 = 30, and 5³ = 125
D works because 5^0 = 1, so we have
5^0(5^3) = 1(5^3) = 5^3
E doesn't work because there is subtraction...
5^3 - 5^0 = 5^3 - 1 = 124
PQ shows the height of the triangle from its base
As P is the highest point of the triangle
and Q lies on the base of the triangle
So PQ is the height of the triangle
And the height of any triangle is also known as the altitude of the triangle
So
PQ is nothing but the Altitude of this triangle
So option D is correct
Altitude
Answer:
t=5.5080( to 3 d.p)
Step-by-step explanation:
From the data given,
n =20
Deviation= 34/20= 1.7
Standard deviation (sd)= 1.3803(√Deviation)
Standard Error = sd/√n
= 1.3803/V20 = 0.3086
Test statistic is:
t = deviation /SE
= 1.7/0.3086 = 5.5080
ndf = 20 - 1 = 19
alpha = 0.01
One Tailed - Right Side Test
From Table, critical value of t =2.5395
Since the calculated value of t = 5.5080 is greater than critical value of t = 2.5395, the difference is significant. Reject null hypothesis.
t score = 5.5080
ndf = 19
One Tail - Right side Test
By Technology, p - value = 0.000
Since p - value is less than alpha , reject null hypothesis.
Conclusion:
From the result obtained it can be concluded that ,the data support the claim that the mean rating assigned to the wine when the cost is described as $90 is greater than the mean rating assigned to the wine when the cost is described as $10.