3 years ago

Question 12 please Tan(a)/ Sec(a)-cos(a)

Mathematics

1 answer:

stepladder [879]3 years ago

4 0

Answer:

Step-by-step explanation:

$\frac{tan ~\alpha }{sec~\alpha -cos~\alpha } \\=\frac{\frac{sin~\alpha }{cos~\alpha } }{\frac{1}{cos~\alpha } -cos~\alpha } \\multiply~numerator~and~denominator~by~cos~\alpha \\=\frac{sin~\alpha }{1-cos^2~\alpha }=\frac{sin~\alpha }{sin ^2~\alpha } \\=\frac{1}{sin~\alpha } \\=cosec~\alpha$

You might be interested in

Vanessa's scale drawing of a volleyball court, shown below, is 3 inches long and 1 1/2 inches wide. How many square meters make

natima [27]

I took a test on this yesterday and all i know is the answer is either 81 117 or 162

6 0

4 years ago

A blueprint shows an apartment with an area of 15 square inches. If the blueprint's scale is 1 inch : 8 feet, what will the actu

Free_Kalibri [48]

I got 480 square feet. I assume that the apartment was a rectangle so the sides were 3in by 5in. Then I converted inches to feet and then found the area again

3 0

3 years ago

Tristen is building 3 trophies using Legos. He needs 324 total Legos. Tristen uses 220 Legos for the largest trophy and 135 Lego

Alexeev081 [22]

Answer: 166

Step-by-step explanation:

Number of trophies = 3

Total Legos required for all trophies = 324

Number of Legos for largest trophy(A) = 220

Number of Legos for smallest trophy(B) = 135

Number of Legos required for final trophy(C)

Total Legos = [Number of Legos for largest trophy(A) + Number of Legos for smallest trophy(B) + Number of Legos required for final trophy(C)]