The correct answer should be A. Delete
Answer:
def typeHistogram(it,n):
d = dict()
for i in it:
n -=1
if n>=0:
if str(type(i).__name__) not in d.keys():
d.setdefault(type(i).__name__,1)
else:
d[str(type(i).__name__)] += 1
else:
break
return list(d.items())
it = iter([1,2,'a','b','c',4,5])
print(typeHistogram(it,7))
Explanation:
- Create a typeHistogram function that has 2 parameters namely "it" and "n" where "it" is an iterator used to represent a sequence of values of different types while "n" is the total number of elements in the sequence.
- Initialize an empty dictionary and loop through the iterator "it".
- Check if n is greater than 0 and current string is not present in the dictionary, then set default type as 1 otherwise increment by 1.
- At the end return the list of items.
- Finally initialize the iterator and display the histogram by calling the typeHistogram.
Answer:
Link Aggregation Control Protocol
Explanation:
Link Aggregation Control Protocol can be used to assist in the formation of port channel bundles of physical links.
Link Aggregation Control Protocol is an IEEE standard defined in IEEE 802.3ad. LACP lets devices send Link Aggregation Control Protocol Data Units (LACPDUs) to each other to establish a link aggregation connection.
Answer:
a. count of observations that meet a condition (counts), total number of observations (nobs), Hypothesized value of population proportion (value).
Explanation:
In other to use the proportion_ztest method, the need to make import from the statsmodel module ; statsmodels.stats.proportion.proportions_ztest ; this will allow use use the Z test for proportion and once this method is called it will require the following arguments (count, nobs, value=None, alternative='two-sided', prop_var=False)
Where;
nobs = number of observations
count = number of successes in the nobs trial or the number of successes for each independent sample.
Value = hypothesized value of the population proportion.
