Answer:
Option B
Step-by-step explanation:
A unit circle means radius of the circle = 1 unit
Let a terminal point on the circle is (x, y) and angle between the point P and x-axis is θ.
Center of the circle is origin (0, 0).
Therefore, ordered pair representing the terminal point will be (OP×Cosθ, OP×Sinθ) = 
OP.Cosθ = 1×Cosθ = 
Cosθ =
θ = 
, 
where n = integers
Similarly, OP×Sinθ = 1×Sinθ = -
Sinθ = -
θ = 
, where n = integer
Common value of θ will be, θ = 
Option B will be the answer.
Answer: 1 1/5 inches.
Step-by-step explanation:
1/5 * 6
1/5 * 6/1
6/5 = 1 1/5
7(a - 10) = 13 - 2(2a + 3)
7a - 70 = 13 - 4a - 6 = 7 - 4a
7a + 4a = 7 + 70
11a = 77
a = 77/11 = 7
a = 7.
c = cost per pound of chocolate chips
w = cost per pound of walnuts.
![\bf \stackrel{\textit{3 lbs of "c"}}{3c}+\stackrel{\textit{5 lbs of "w"}}{5w}~~=~~\stackrel{\textit{costs}}{15} \\\\\\ \stackrel{\textit{12 lbs of "c"}}{12c}+\stackrel{\textit{2 lbs of "w"}}{2w}~~=~~\stackrel{\textit{costs}}{33} \end{cases}\qquad \impliedby \textit{let's use elimination} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{llccccccl} 3c+5w=15&\times (-4)\implies &-12c&+&-20w&=&-60\\ 12c+2w=33&&12c&+&2w&=&33\\ \cline{3-7}\\ &&0&&-18w&=&-27 \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7B3%20lbs%20of%20%22c%22%7D%7D%7B3c%7D%2B%5Cstackrel%7B%5Ctextit%7B5%20lbs%20of%20%22w%22%7D%7D%7B5w%7D~~%3D~~%5Cstackrel%7B%5Ctextit%7Bcosts%7D%7D%7B15%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7B12%20lbs%20of%20%22c%22%7D%7D%7B12c%7D%2B%5Cstackrel%7B%5Ctextit%7B2%20lbs%20of%20%22w%22%7D%7D%7B2w%7D~~%3D~~%5Cstackrel%7B%5Ctextit%7Bcosts%7D%7D%7B33%7D%20%5Cend%7Bcases%7D%5Cqquad%20%5Cimpliedby%20%5Ctextit%7Blet%27s%20use%20elimination%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllccccccl%7D%203c%2B5w%3D15%26%5Ctimes%20%28-4%29%5Cimplies%20%26-12c%26%2B%26-20w%26%3D%26-60%5C%5C%2012c%2B2w%3D33%26%2612c%26%2B%262w%26%3D%2633%5C%5C%20%5Ccline%7B3-7%7D%5C%5C%20%26%260%26%26-18w%26%3D%26-27%20%5Cend%7Barray%7D)
The halves of the rhombus separated by line BD are equilateral triangles.
∠BAD = 60°
so
∠ADM is 0.80*60° = 48°.
∠BMD is an exterior angle to ΔAMD, so is equal to the sum
∠BMD = ∠BAD + ∠ADM
= 60° +48° = 108°
∠BMD = 108°
