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Vera_Pavlovna [14]
3 years ago
11

The circle above has an area of 36 in2. What is the area of the blue sector? Use 3.14 for .

Mathematics
1 answer:
grandymaker [24]3 years ago
7 0
<span>your answer will be 3 in^2  :)</span>
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Kelly has some apples, bananas and oranges. The ratio of the number of apples to the total number of fruits us 1:4. There are 30
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Total fruits→120=4u
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PLEASE HELP ME!!!!!!
Sonja [21]

Answer:

\huge \red{ c_3 = - 1}

Step-by-step explanation:

c_1 = 1 \\  \\ c_n= - 2c_{n-1}+5 \\  \\ c_2 = - 2c_{2-1}+5 \\  \\ c_2 = - 2c_{1}+5 \\  \\ c_2 = - 2(1)+5 \\  \\ c_2 = - 2+5 \\  \\  \huge \purple{c_2 =3} \\  \\ c_3 = - 2c_{3-1}+5 \\  \\ c_3 = - 2c_{2}+5 \\  \\ c_3 = - 2(3)+5 \\  \\ c_3= - 6+5 \\  \\ \huge \red{ c_3 = - 1}

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ki77a [65]

Answer:

fffgfdfgee

Step-by-step explanation:

5 0
3 years ago
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It is estimated % of all adults in United States invest in stocks and that % of U.S. adults have investments in fixed income ins
katovenus [111]

Complete question :

It is estimated 28% of all adults in United States invest in stocks and that 85% of U.S. adults have investments in fixed income instruments (savings accounts, bonds, etc.). It is also estimated that 26% of U.S. adults have investments in both stocks and fixed income instruments. (a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places. (b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?

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0.929 ; 0.306

Step-by-step explanation:

Using the information:

P(stock) = P(s) = 28% = 0.28

P(fixed income) = P(f) = 0.85

P(stock and fixed income) = p(SnF) = 26%

a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places.

P(F|S) = p(FnS) / p(s)

= 0.26 / 0.28

= 0.9285

= 0.929

(b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?

P(s|f) = p(SnF) / p(f)

P(S|F) = 0.26 / 0.85 = 0.3058823

P(S¦F) = 0.306 (to 3 decimal places)

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