Answer:
(Choice A) A graph of an increasing linear function in quadrant 1 with a positive y-intercept.
Step-by-step explanation:
The weight of the sumo wrestler starts at a positive value of 79.5 kilograms, and we are given that the sumo wrestler gains a linear amount of weight per month at 5.5 kilograms per month.
If we were to graph this relationship, the sumo wrestler's weight would be represented on the y-axis, and the amount of time on the x-axis.
So the initial weight would occur at (0, 79.5) which is the positive y-intercept.
And since his weight is increasing at 5.5 kilograms per month, the slope of the linear function is positive.
Hence, the graph of the linear increasing function in quadrant 1 with a positive y-intercept.
Cheers.
Answer:
the differentiation d/dx will be ..... -5x^-6
Sum refers to the answer of an addition problem. So:
914 + 878
<span>1792
</span>
Hope this helps!
$6 * 5 = $30
5 * $4 = $20
We don't know what the student council savings were to begin with in this project, soooo, this is as far as I got. What do you think?
<h2><u>
Answer with explanation</u>
:</h2>
Given: In Δ ABC and ΔAEC,
AB=BC and AD=CD
i) In ΔADB and CBD, we have
AD = DC [given]
AB=BC [given]
DB= DB [given]
⇒ ΔADB ≅ΔCDB [By SSS congruence rule]
⇒ ∠ADB ≅∠CDB ...(i) [Corresponding parts of congruent triangles are congruent]
Since AC is a straight line,
∠ADB+∠CDB = 180° [Linear pair]
⇒∠ADB+∠ADB=180° [from (i)]
⇒2 ∠ADB=180°
⇒∠ADB=90° =∠CDB
Also ∠ADB+∠ADE=180° [Linear pair]
⇒∠ADE=180°-∠ADB = 180°-90°
⇒∠ADE=90°, i.e. ∠ADE is a right triangle.
Similarly, ∠CDB+∠CDE=180°
⇒∠CDE=90°
ii) Now, in ΔADE and CDE
AD= CD [given]
ED=ED [Common]
∠ADE= ∠CDE = 90°
⇒ΔADE ≅ CDE [By SAS congruence rule ]
⇒AE=EC [Corresponding parts of congruent triangles are congruent]
Hence proved.
