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3 years ago

Which set of side lengths forms a right triangle?

Mathematics

1 answer:

pochemuha3 years ago

4 0

Awnser:

9,12,18

Step-by-step explanation:

you have to add the smallest numbers together and it has to be greater that the greatest number.

9+12= 21

21>18

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Rectangle A is a scale drawing of Rectangle B and has 25% of its area. If rectangle A has side lengths of 4 cm and 5 cm , what a

SpyIntel [72]

Answer:

8 cm and 10 cm

Step-by-step explanation:

Hello, <em> </em>I can help you with this.

Step 1

According to the question there are two rectangles A and B,

Rectangle A is a scale drawing of Rectangle B and has 25% of its area

in other words

$Area_{A}=0.25*Area_{B} (Equation\ 1)\\$

Step 2

Let

Rectangle A

length (1)= 4 cm

length (2)= 5 cm

$Area_{A}=4\ cm * 5\ cm\\Area_{A}=20\ cm^{2}$

put this value into equation 1

$Area_{A}=0.25*Area_{B} (Equation\ 1)\\\\20\ cm^{2} =0.25*Area_{B} \\divide\ each\ side\ by\ 0.25\\\frac{20\ cm^{2} }{0.25}=\frac{0.25}{0.25}*Area_{B}\\ Area_{B}=80\ cm^{2}$

Now, we know the area of rectangle B, to know its length we need to formule other equation

Step 3

$Area_{B}=80\ cm^{2}\\length (1B)*length (2B)=80\ cm^{2} (equation\ 2)\\$

the ratio between the lengths must be constant, so the ratio of A must be equal to ratio in B, then

$\frac{length(1A)}{length(2A)}=\frac{length(1B)}{length(2B)} \\\\\\frac{4}{5}= \frac{length(1B)}{length(2B)}\\0.8=\frac{length(1B)}{length(2B)}\\length(1B)=0.8*length(2B) (Equation 3)$

Step three

using Eq 1 and Eq 2 find the lengths

put the value of length(1B) into equation (2)

$length (1B)*length (2B)=80\ cm^{2} (equation\ 2)\\\(0.8*length(2B)) (*length (2B)=80\ cm^{2} \\\\0.8*(length (2B))^{2} =80\ cm^{2}\\(length (2B))^{2} =\frac{80\ cm^{2}}{0.8} \\(length (2B))^{2}=100\\\sqrt{(length (2B))^{2}}=\sqrt{100\ cm^{2}} \\ length (2B)=10\ cm$

Now, put the value of length(2B) into equation 3 to know length (1B)

$length(1B)=0.8*length(2B)\\length(1B)=0.8*10\ cm\\length(1B)=8 cm$

I really hope this helps you, have a great day.

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3 years ago

Who wants to watch some henti with me

melomori [17]

Answer:

SOAP TRUSTED YOU!

I THOUGHT I COULD TOO

SO WHY IM BLOODY HELL DOES MAKOROV KNOW YOU!!!

7 0

2 years ago

A necklace and earrings cost $144. Six necklaces and five pairs of earrings cost $825

hram777 [196]

Step-by-step explanation:

let necklace : x

let earrings : y

x+y=144 -1st eqn

6x+5y=825 -2nd eqn

y=144-X -3rd eqn

substitute eqn into 2nd eqn

6x+5(144-x)= 825

6x +720-5X =825 (expanded)

X = 825-720

X =105

substitute "X=105" into 1st eqn

(105)+y=144

y= 144-105

y=39

1 necklace = 105$

1 pair of earrings = 39$

(to check back: substitute the value into the original eqn)

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2 years ago

A flat-creen tv costs $1,400.00. the tv is on sale for 35% off. what is the discounted price of the tv

Vinvika [58]

$910.00 is the answer

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2 years ago

Algebra Vocab help? (25 points)

oee [108]

3
6
1
4
2
5

I hope this helps :)

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2 years ago