Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
It's 13
Step-by-step explanation:
Well, just use the triangle inequality theorem and pay close attention to angles CAB and EAC... that's all I can say
Hope that helped
It’s either Option 1 or 4
Answer:
Sorry I am a little confused about the answer
#7:
<span>Subtract </span>y<span> from both sides:
</span>-4x=6-y
Divide both sides by -4:
Answer:
x= -6-y/4
#7 part 2:
Add <span>y</span><span> to both sides:
</span>-5x=21+y
Divide both sides by -5:
Answer: x=-21+y/5
hope i helped!
