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Ghella [55]
2 years ago
7

Which statements must be true regarding the two triangles? Check all that apply. M M" O LMN - L"M"N" O LMN 2 L"M"N"

Mathematics
2 answers:
blagie [28]2 years ago
8 0

Answer: The 1st, 2nd, and 5th one

Step-by-step explanation:

just did it

Ratling [72]2 years ago
5 0

Answer:

I think it's the first, second, and fifth option.

Step-by-step explanation:

I hope this helps.

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A rectangular container can hold 45 candles, while a cylindrical container holds 41 candles. Each rectangular
kap26 [50]

Answer:

  a) no

  b) 143 rectangular containers

  c) 157 cylindrical containers

  d) both (preferring rectangular for the bulk of an order)

Step-by-step explanation:

a) If the company needs to package 6,400 candles, should it use only rectangular or only cylindrical containers to minimize costs?

  No.*

For packaging 41 candles or fewer, the cylindrical container costs less than the rectangular one.

For packaging 6400 candles, there will be 10 candles left over if rectangular containers are used for most of the packaging needs. A dollar can be saved by packaging these remaining candles in a cylindrical container.

__

b) How many rectangular containers will be necessary to package 6,400 candles?

  6400/45 = 142 10/45

If rectangular containers are used for all, then 143 are needed.

__

c) How many cylindrical containers will be necessary to package 6,400 candles?

  6400/41 = 156 4/41

If cylindrical containers are used for all, the 157 are needed.

__

d) Which container should the company use to minimize costs?

  The cost of 143 rectangular containers is 143×$16 = $2288

  The cost of 157 cylindrical containers is 157×$15 = $2355

  The cost of 142 rectangular and 1 cylindrical container is $2287

If only one shape container is used, the company should use rectangular containers to minimize cost. If either shape can be used, cost will be minimized by using one cylindrical container for the remnant of the order.

_____

* This question is directed solely at the cost of materials required for packaging. We have advocated that both rectangular and cylindrical containers be made available. As a practical matter, the cost to the company of maintaining inventory of both sizes of containers may exceed the savings associated with using a cheaper container for smaller orders.

8 0
3 years ago
Greg withdrew $37 from his account on Wednesday and then deposited $15 in his account on Thursday. On Friday, he withdrew $120.
barxatty [35]

he had $297 in his account before wednesday

5 0
3 years ago
Please help.... what is it’s measure
Olegator [25]

right

Answer:

90°

Step-by-step explanation:

Type of angle foremd= right

Measure = 40° + 50° = 90°

8 0
3 years ago
Read 2 more answers
1+1+2+3+4 is what<br> it says it needs to be 20 characters long
dlinn [17]

Answer:

11

Step-by-step explanation:

how do you know how to read yet not know this

7 0
3 years ago
Recent census data indicated that 14.2% of adults between the ages of 25 and 34 live with their parents. A random sample of 125
kicyunya [14]

Answer:

The  probability is  P(14 <  X  <  20 ) =  0.5354  

Step-by-step explanation:

From the question we are told that

   The  proportion that live with their parents is  \r p  =  0.142

   The  sample  size is n =  125

   

Given that there are two possible outcomes and that this outcomes are independent of each other then we can say the Recent census data follows a Binomial distribution

  i.e  

       X   \  \~ \ B( \mu ,  \sigma )

Now the mean is evaluated as

      \mu  =  n *  \r p

      \mu  =  125 *  0.142

      \mu  =  17.75

Generally the proportion that are not staying with parents is  

      \r  q  =  1 -  \r  p

= >    \r  q  =  0.858

The standard deviation is mathematically evaluated as

     \sigma  =  \sqrt{n * \r p  *  \r q }

     \sigma  =  \sqrt{ 125 *  0.142 * 0.858  }

    \sigma  = 3.90

Given the n is large  then we can use normal approximation to evaluate the probability as follows  

     P(14 <  X  <  20 ) =  P( \frac{ 14 -  17.75}{3.90}

Now applying continuity correction

      P(14 <  X  <  20 ) =  P( \frac{ 13.5 -  17.75}{3.90}  < \frac{  X  - \mu }{\sigma } < \frac{ 19.5 -  17.75}{3.90}   )

Generally  

    \frac{  X  - \mu }{\sigma }  =  Z  ( The  \ standardized \ value  \  of  X )

    P(14 <  X  <  20 ) =  P( \frac{ 13.5 -  17.75}{3.90}  < Z< \frac{ 19.5 -  17.75}{3.90}   )

     P(14 <  X  <  20 ) =  P( -1.0897   < Z<  0.449 }   )

    P(14 <  X  <  20 ) =   P( Z<  0.449   ) - P(Z  <   -1.0897)

So  for the z -  table  

         P( Z<  0.449   ) =  0.67328

         P(Z  <   -1.0897)  = 0.13792

 P(14 <  X  <  20 ) =   0.67328 -  0.13792    

  P(14 <  X  <  20 ) =  0.5354  

     

6 0
3 years ago
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