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jolli1 [7]
3 years ago
5

Does anyone have remind if so i will give u a code ??? iii

Mathematics
2 answers:
Inessa05 [86]3 years ago
7 0

Answer:

I'm so confused, what are you trying to say? lol

Allisa [31]3 years ago
3 0

Answer:

sure

Step-by-step explanation:

i'll join

can provide memes

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Sally paid the following bills rent $450.00 cell phone $37.50 and cable $69.99 how much money did she pay ?
romanna [79]

Answer:

557.49

Step-by-step explanation:

Add the three bills together

450.00

 37.50

 69.99

--------------

557.49

3 0
3 years ago
What calculation can I use to find 961 after a 24% decrease?
dsp73

Answer:

d

Step-by-step explanation:

i know it's rhe right answer

5 0
2 years ago
Read 2 more answers
6x+5x-8=-41 what property is this ?
Allisa [31]

Standard form

6x+5x-8 =-41

Is in standard form

6 0
3 years ago
Dequan is training for a marathon. He runs 20 miles every 4 days. What is the unit rate for Dequan?
KonstantinChe [14]

Answer:

Dequan walks 5 miles per day.

Step-by-step explanation:

So solve this problem, we just need to divide 20 miles by 4 days.

20 ÷ 4 = 5

Therefore, Dequan walks 5 miles per day.

Hope this helps! :D

5 0
3 years ago
Read 2 more answers
A lidless box is to be made using 2m^2 of cardboard find the dimensions of the box that requires the least amount of cardboard
Jlenok [28]
1.8, Problem 37: A lidless cardboard box is to be made with a volume of 4 m3 . Find the dimensions of the box that requires the least amount of cardboard. Solution: If the dimensions of our box are x, y, and z, then we’re seeking to minimize A(x, y, z) = xy + 2xz + 2yz subject to the constraint that xyz = 4. Our first step is to make the first function a function of just 2 variables. From xyz = 4, we see z = 4/xy, and if we substitute this into A(x, y, z), we obtain a new function A(x, y) = xy + 8/y + 8/x. Since we’re optimizing something, we want to calculate the critical points, which occur when Ax = Ay = 0 or either Ax or Ay is undefined. If Ax or Ay is undefined, then x = 0 or y = 0, which means xyz = 4 can’t hold. So, we calculate when Ax = 0 = Ay. Ax = y − 8/x2 = 0 and Ay = x − 8/y2 = 0. From these, we obtain x 2y = 8 = xy2 . This forces x = y = 2, which forces z = 1. Calculating second derivatives and applying the second derivative test, we see that (x, y) = (2, 2) is a local minimum for A(x, y). To show it’s an absolute minimum, first notice that A(x, y) is defined for all choices of x and y that are positive (if x and y are arbitrarily large, you can still make z REALLY small so that xyz = 4 still). Therefore, the domain is NOT a closed and bounded region (it’s neither closed nor bounded), so you can’t apply the Extreme Value Theorem. However, you can salvage something: observe what happens to A(x, y) as x → 0, as y → 0, as x → ∞, and y → ∞. In each of these cases, at least one of the variables must go to ∞, meaning that A(x, y) goes to ∞. Thus, moving away from (2, 2) forces A(x, y) to increase, and so (2, 2) is an absolute minimum for A(x, y).
5 0
3 years ago
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