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labwork [276]
3 years ago
7

Examine the system of equations. −5x + 5y = 40 4x + 3y = 24 What is the solution?

Mathematics
2 answers:
Solnce55 [7]3 years ago
3 0
-5x + 5y = 40             -20x +20y =160               -5x + 5(8) = 40
4x + 3y = 24               20x +15y =120                -5x + 40 = 40
                                           35y = 280                   -5x =0
                                               y = 8                         x = 0

Hope you understood this
densk [106]3 years ago
3 0
The solution is (0,8). I solved this system of equations by using substitution.
  
1).      -5x + 5y = 40
         + 5x         + 5x
----------------------------------
          5y = 5x + 40
       -------  ----  ------
          5       5      5
 
           y = x + 8

__________________________________________________________

2).  4x + 3(x  + 8) = 24
       4x + 3x + 24 = 24

       7x + 24 = 24
             - 24   -24
    -----------------------
       7x = 0 
      ----   ----
       0      0

        x = 0
__________________________________________________________

3).  -5(0) + 5y = 40
       
        0 + 5y = 40

        5y = 40
       ----   ------
        5       5
  
        y = 8
__________________________________________________________




   



  


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Step-by-step explanation:

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\sqrt{(a^{2}+b^{2} )}=\sqrt{(1^{2}+(\frac{1}{\sqrt{3} }) ^{2} )}\\=\sqrt{\frac{4}{3}}\\=\frac{2}{\sqrt{3} }

Now, Dividing both the side by \frac{2}{\sqrt{3} } we get

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Now by replacing with above values we get

\sin 60\times \cos x + \cos 60\times \sin x = \frac{\sqrt{3} }{2}\\

Also we have formula

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By applying the above Formula we get

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Therefore, the values are x = 0° or x = 60° i.e between 0° to 360°

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