All categories

3 years ago

Which expressions are equivalent to the given expression?

Mathematics

1 answer:

Komok [63]3 years ago

5 0

-51 - 6i AND -3 + 2i - 2(24) - 8i are correct :)

You might be interested in

1/4 c=__pt? Fill the blank

jonny [76]

Step-by-step explanation:

A pint has 2 cups

2 cups = 1 pint

1 cup = 1/2 pint

1/4 cup = 1/2 ÷ 4 = 1/2 * 1/4 = 1/8 pint

3 0

3 years ago

Rewrite 1 / 6 barrels over 2 over 5 hours as a unit rate

Akimi4 [234]

Answer:

5/12 barrel/hour

Step-by-step explanation:

Type this as a fraction:

(1/6) barrel

--------------------

(2/5) hours

Division by 2/5 is equivalent to multiplication by 5/2:

1 5

--- barrel * -------------- = 5/12 barrel/hour

6 2 hours

Alternatively, this problem could be done using decimal fractions:

0.1667 barrel

-------------------- = 0.416666 barrel/hour = 5/12 barrel/hour

0.4 hours

5 0

3 years ago

A polyhedron has 8 vertices and 14 edges. How many faces must it have?

Scorpion4ik [409]

We know that

The Euler's formula state that, the number of vertices, minus the number of edges, plus the number of faces, is equal to two

V - E + F = 2
clear F
F=2-V+E

in this problem
V=8
E=14
F=?
so
F=2-8+14
F=8

the answer is
8 faces

7 0

3 years ago

Mystery Boxes: Breakout Rooms

ollegr [7]

Answer:

$\begin{array}{ccccccccccccccc}{1} & {3} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {57} & {58} & {61} \\ \end{array}$

Step-by-step explanation:

Given

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {[ \ ]} \\ \end{array}$

Required

Fill in the box

From the question, the range is:

$Range = 60$

Range is calculated as:

$Range = Highest - Least$

From the box, we have:

$Least = 1$

So:

$60 = Highest - 1$

$Highest = 60 +1$

$Highest = 61$

The box, becomes:

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

From the question:

$IQR = 20$ --- interquartile range

This is calculated as:

$IQR = Q_3 - Q_1$

$Q_3$ is the median of the upper half while $Q_1$ is the median of the lower half.

So, we need to split the given boxes into two equal halves (7 each)

Lower half:

$\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } \\ \end{array}$

Upper half

$\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

The quartile is calculated by calculating the median for each of the above halves is calculated as:

$Median = \frac{N + 1}{2}th$

Where N = 7

So, we have:

$Median = \frac{7 + 1}{2}th = \frac{8}{2}th = 4th$

So,

$Q_3$ = 4th item of the upper halves

$Q_1$ = 4th item of the lower halves

From the upper halves

$\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

We have:

$Q_3 = 32$

$Q_1$ can not be determined from the lower halves because the 4th item is missing.

So, we make use of:

$IQR = Q_3 - Q_1$

Where $Q_3 = 32$ and $IQR = 20$

So:

$20 = 32 - Q_1$

$Q_1 = 32 - 20$

$Q_1 = 12$

So, the lower half becomes:

Lower half:

$\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {12 } & {15} & {18}& {[ \ ] } \\ \end{array}$

From this, the updated values of the box is:

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$