2 years ago

Which expressions are equivalent to the given expression?

Mathematics

1 answer:

Komok [63]2 years ago

5 0

-51 - 6i AND -3 + 2i - 2(24) - 8i are correct :)

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Simplify when it is possible 10 x^2 - y + x^2

Romashka-Z-Leto [24]

Combine like terms
11x^2 - y

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3 years ago

50pts PLEASE HURRY UP I WILL GIVE BRAINLEST SHOW ALL OF YOUR WORK ANSWER ALL THE QUESTIONS

blagie [28]

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In two spins, there are 9 possible outcomes: AA, AB, AC, BA, BB, BC, CA, CB, CCIf we assume each of these is equally likely, then the probability of AB or BA is ... 2/9

Step-by-step explanation:

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1 year ago

If 5 out of 25 people like chocolate ice cream, what percent of the people do not like chocolate ice cream

d1i1m1o1n [39]

100 - ((5÷25)x100),
hence C. 80%

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2 years ago

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Help me please!!!!!!!!!!!!!!!!

Sav [38]

Answer:

x=-4 and y=4

Step-by-step explanation:

(6x+9y)-(6x+7y)=12-4=8

--> 9y-7y=8

-->2y=8-->y=4

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2 years ago

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The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

Part C

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

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2 years ago