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fenix001 [56]
3 years ago
11

In a recent school newspaper survey, 3,000 randomly selected teenagers were asked to cite their primary transportation method to

school. Fifteen of 20 teenagers said they use their own car to get to school. A 90% confidence interval to estimate the true proportion of teenagers who drive their own car to school is found to be (0.5907, 0.9093). Which of the following is a correct interpretation of the confidence level?
Ninety percent of the time, the procedure used to generate this interval will capture the true proportion of teenagers who drive their own car to school.

Ninety percent of all samples of this size would yield a confidence interval of (0.5907, 0.9093). (not correct)

There is a 90% chance that the true proportion of teenagers who drive their own car to school will be (0.5907, 0.9093).

Ninety percent of all the samples of size 3,000 lie in the confidence interval (0.5907, 0.9093).

There is a 90% chance that randomly selected teenagers will be part of the 75% who drive their own car to school.
Mathematics
1 answer:
Verizon [17]3 years ago
7 0

Answer: There is a 90% chance that the true proportion of teenagers who drive their own car to school will lie in (0.5907, 0.9093).

Step-by-step explanation:

Interpretation of a% confidence interval : A person can be a% confident that the true population parameter lies in it.

Here, A 90% confidence interval to estimate the true proportion of teenagers who drive their own car to school is found to be (0.5907, 0.9093).

i.e. A person can be 90% confident that  the true proportion of teenagers who drive their own car to school lies in (0.5907, 0.9093).

Hence, correct interpretation is : There is a 90% chance that the true proportion of teenagers who drive their own car to school will lie in (0.5907, 0.9093).

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3 hours

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Solve for a. m=a/9-H
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Answer:

9(m+H) = a

Step-by-step explanation:

m=a/9-H

The first step is to add H to each side.

m+H = a/9 -H+H

m+H = a/9

Now multiply both side by 9

9(m+H) = a/9*9

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Find the sine of ∠W.
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3 0
2 years ago
Suma a 3 numere naturale este 163. Scazand al treilea numar din suma primelor doua numere, obtinem 67. Scazand primul numar din
Vika [28.1K]

Answer: x=63, y=52, z=48

Step-by-step explanation:

The complete question in english is:

The sum of 3 natural numbers is 163. By subtracting the third number from the sum of the first two numbers, we get 67. By subtracting the first number from the sum of the last 2 numbers, we get 37. Determine the 3 numbers

According to this we have a system with three equations and three unknown values:

x+y+z=163 (1)

x+y-z=67 (2)

-x+y+z=37 (3)

Let's begin by isolating x from (1):

x=163-y-z (4)

And substitute (4) in (2):

163-y-z+y-z=67 (5)

Isolating z:

z=48 (6) We have found the first number

Substituting (6) in (1):

x+y+48=163 (7)

Adding (7) to (3):

\left \{ {{x+y+48=163} \atop {-x+y+z=37}} \right

We have the following:

2y+96=200

Isolating y:

y=52 (8) This is the second number

Substituting (6) and (8) in (1):

x+52+48=163 (9)

Isolating x:

x=63 (10) This is the third number

8 0
4 years ago
There is a jar on the cabinet by the refrigerator. If Keona pours 114 ounces of water into the jar three times to fill it, how m
I am Lyosha [343]

The amount of quarts of water to fill the jar is 10.6875 quarts

To solve this problem effectively, we need to understand the concept of word problems.

<h3>What are word problems in mathematics?</h3>

Word problems in mathematics are questions that require a crucial understanding and application of mathematical principles to solve them effectively.

From the parameters given:

  • If 114 ounces of water is poured three times to fill the jar

Then, the total amount of ounces that fills the water is:

= 114 ounces × 3

= 342 ounces

From the dimensional analysis of measurements:

1 ounce = 0.03125 quarts

Thus, in quarts, 342 ounces will be:

\mathbf{=\dfrac{ (342 \  ounces \times 0.03125 \ quarts)}{1 \ ounce}}

= 10.6875 quarts

Learn more about word problems in mathematics here:

brainly.com/question/21405634

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3 years ago
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