All categories

2 years ago

The binomial (a+5) is a factor of a2+7a+10. What is the other factor?

Mathematics

1 answer:

aliya0001 [1]2 years ago

5 0

Answer:

(a+2)

Step-by-step explanation:

a²+7a+10 = (a + 5) (a + 2)

a + 5

X <em>5a + ?a = 7a => 5a + 2a = 7a, 5 × ? = 10 => 5 × 2 = 10</em>

a + <em>2</em>

______

(a + 5) (a + 2)

You might be interested in

1. [-/1 Points]

stiv31 [10]

multiply x times y divide by 6 on both sides and you got your answer

4 0

7 months ago

I really need help guys can some one plz help me it's for 10 points

11111nata11111 [884]

Answer:

$\sqrt{8}----- 2units,2units$

$\sqrt{7} ------\sqrt{5}units,\sqrt{2}units$

$\sqrt{5}-------1unit,2units$

$3------2units, \sqrt{5}units$

Step-by-step explanation:

Use pythagorean's theorem to solve each pair individually.

The instructions say that you have the two sides (a and b) and you have to match it with their hypothenuse.

$Formula: c^2=a^2+b^2$

1. $a=\sqrt{5}, b=\sqrt{2}$

Plug this into the formula.

$c=\sqrt{(\sqrt{5} )^2+(\sqrt{2})^2 }$

The square here eliminates the roots.

$c=\sqrt{5+2}\\ c=\sqrt{7}$

2. $a=\sqrt{3}, b=4$

$c=\sqrt{(\sqrt{3} )^2+(4)^2}\\ c=\sqrt{3+16}\\ c=\sqrt{19}$

3. $a=2, b=\sqrt{5}$

$c=\sqrt{(2)^2+(\sqrt{5})^2 }\\ c=\sqrt{4+5}\\ c=\sqrt{9}\\ c=3$

4. $a=2, b=2$

$c=\sqrt{(2)^2+(2)^2}\\ c=\sqrt{4+4}\\ c=\sqrt{8}$

5. $a=1, b=2$

$c=\sqrt{(1)^2+(2)^2}\\ c=\sqrt{1+4}\\ c=\sqrt{5}$

7 0

2 years ago

Solve 10/12 - 3/8 show your solution as an equation

elena55 [62]

Answer:

11/24

Step-by-step explanation:

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator. Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1. The two fractions now have like denominators so you can subtract the numerators.

This fraction cannot be reduced.

Therefore the answer is 11/24

7 0

2 years ago

Read 2 more answers

What is the reason for Statement 3 of the two-column proof?

Ivenika [448]

Refer to the attached image.

Given:

The measure of $\angle JMK= 52^\circ$ and $\angle KML= 38^\circ$ .

Also, Three rays ML, MK, and MJ share an endpoint M. Ray MK forms a bisector as shown in the attached image and the bisector divides angle JML into two parts.

To Prove: $\angle JML$ is a right angle.

Proof:

Statements Reasons

1. $m \angle JMK=52^\circ$ Given

2. $m \angle KML=38^\circ$ Given

3. $m \angle JMK+m \angle KML=m \angle JML$

The reason for statement 3 is Angle addition postulate. As angle JML is composed of 2 angles that is angle JMK and angle KML. So by adding the measures of angles JMK and KML, we will get the measure of angle JML which is referred as Angle addition postulate.

4. $52^\circ+38^\circ = m \angle JML$ Substitution property of equality