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4 years ago

What is the answer to 3+5

Mathematics

2 answers:

Llana [10]4 years ago

4 0

8 is 3+5, that would be the correct answer

Roman55 [17]4 years ago

3 0

3+5=8

Hope This Helps and God Bless!

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I need your help again guys!

solmaris [256]

ANSWER

$x = 13$

EXPLANATION

Use the Pythagoras Theorem to obtain,

${x}^{2} = {12}^{2} + {5}^{2}$

This implies that,

${x}^{2} = 144 + 25$

${x}^{2} = 169$

Take the positive square root of both sides to get,

$x = \sqrt{169}$

$x = 13$

8 0

4 years ago

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Tom and Jason both collect marbles Tom has collected 510 marbles and Jason has collected 842 marbles. How many marbles do they o

dezoksy [38]

Answer:

They had 1,352 marbles all together, rounded to the nearest hundred, 1,400.

Step-by-step explanation:

All we have to do is add the number of marbles they collected.

510 + 842 = 1,352

1,352 rounded to the nearest hundred is 1,400.

7 0

3 years ago

Read 2 more answers

Which one is correct ?

olga55 [171]

Give the two exterior angles of 133 and 142, we can deduce that the interior angles are 47 and 38, respectively. In fact, if $i$ and $e$ are the interior and exterior angles, respectively, we have

$i=180-e$

Now, the interior angles of a triangle sum up to 180 degrees. Since we already have angles of 47 and 38 degrees, the missing angle is

$180-47-38=95$

Which implies

$n=180-95=85$

3 0

3 years ago

Why is renting sometimes considered “throwing money away”?

Leona [35]

Answer:

cuz they ask for an interest with the increase of time

7 0

3 years ago

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A common assumption in modeling drug assimilation is that the blood volume in a person is a single compartment that behaves like

mixas84 [53]

Answer:

a) $\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}$

b) $\mathbf{x = 2000 - 2000e^{-0.015t}}$

c) the steady state mass of the drug is 2000 mg

d) t ≅ 153.51 minutes

Step-by-step explanation:

From the given information;

At time t= 0

an intravenous line is inserted into a vein (into the tank) that carries a drug solution with a concentration of 500

The inflow rate is 0.06 L/min.

Assume the drug is quickly mixed thoroughly in the blood and that the volume of blood remains constant.

The objective of the question is to calculate the following :

a) Write an initial value problem that models the mass of the drug in the blood for t ≥ 0.

From above information given :

$Rate _{(in)}= 500 \ mg/L \times 0.06 \ L/min = 30 mg/min$

$Rate _{(out)}=\dfrac{x}{4} \ mg/L \times 0.06 \ L/min = 0.015x \ mg/min$

Therefore;

$\dfrac{dx}{dt} = Rate_{(in)} - Rate_{(out)}$

with respect to x(0) = 0

$\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}$

b) Solve the initial value problem and graph both the mass of the drug and the concentration of the drug.

$\dfrac{dx}{dt} = -0.015(x - 2000)$

$\dfrac{dx}{(x - 2000)} = -0.015 \times dt$

By Using Integration Method:

$ln(x - 2000) = -0.015t + C$

$x -2000 = Ce^{(-0.015t)$

$x = 2000 + Ce^{(-0.015t)}$

However; if x(0) = 0 ;

Then

C = -2000

Therefore

$\mathbf{x = 2000 - 2000e^{-0.015t}}$

c) What is the steady-state mass of the drug in the blood?

the steady-state mass of the drug in the blood when t = infinity

$\mathbf{x = 2000 - 2000e^{-0.015 \times \infty }}$

x = 2000 - 0

x = 2000

Thus; the steady state mass of the drug is 2000 mg

d) After how many minutes does the drug mass reach 90% of its stead-state level?

After 90% of its steady state level; the mas of the drug is 90% × 2000

= 0.9 × 2000

= 1800

Hence;

$\mathbf{1800 = 2000 - 2000e^{(-0.015t)}}$

$0.1 = e^{(-0.015t)$

$ln(0.1) = -0.015t$

$t = -\dfrac{In(0.1)}{0.015}$

t = 153.5056729

t ≅ 153.51 minutes

4 0

3 years ago