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Tom [10]
4 years ago
9

A low calorie dinner has 480 calories in an 9ounce serving what is the simplest form

Mathematics
1 answer:
iren2701 [21]4 years ago
6 0

Answer:

The simplest form of 480 calories in a 9 ounce serving is 53.34 calories in one ounce.

Step-by-step explanation:

\frac{480calories}{9ounces} ; simplest form = \frac{blankcalories}{1ounce}

Since the ounces are the denominators, to get from 9 ounces to one ounce we had to divide 9 by 9. What we do to the top we must do to the bottom.

480 calories ÷ 9 = 53.34 .

∴ the simplest form of 480 calories in a 9 ounce serving is 53.34 calories in one ounce.

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olga_2 [115]

Answer:

516 cm squared

Step-by-step explanation:

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How do we do it?

  1. Calculate each face of the prism by multiplying Length x Width.
  2. Make a shortcut by combining like-figures (front of the cube and back of the cube are the same surface areas, etc.)
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  • 2(4 · 15) + 2(10 · 15) + 2(12 · 4)

6 0
3 years ago
6x + 14 = 20x – 14 <br> need the answer
xenn [34]

Answer:

x = 2

Step-by-step explanation:

6x + 14 = 20x - 14

subtract 20x from both sides

-14x + 14 = -14

divide both sides by -14

x - 1 = 1

add 1 to both sides

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5 0
3 years ago
What is the average diastolic blood pressure for adults
kolezko [41]

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Step-by-step explanation:

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8 0
4 years ago
Read 2 more answers
Answer for a lot of points!
earnstyle [38]

Given :

  • ZC = 90°

  • CD is the altitude to AB.

  • \angleA = 65°.

To find :

  • the angles in △CBD and △CAD if m∠A = 65°

Solution :

In Right angle △ABC,

we have,

=> ACB = 90°

=> \angleCAB = 65°.

So,

=> \angleACB + \angleCAB+\angleZCBA = 180° (By angle sum Property.)

=> 90° + 65° + \angleCBA = 180°

=> 155° +\angleCBA = 180°

=> \angleCBA = 180° - 155°

=> \angleCBA = 25°.

In △CDB,

=> CD is the altitude to AB.

So,

=> \angle CDB = 90°

=> \angleCBD = \angleCBA = 25°.

So,

=> \angleCBD + \angleDCB = 180° (Angle sum Property.)

=> 90° +25° + \angleDCB = 180°

=> 115° + \angleDCB = 180°

=> \angleDCB = 180° - 115°

=> \angleDCB = 65°.

Now, in △ADC,

=> CD is the altitude to AB.

So,

=> \angleADC = 90°

=>\angle CAD =\angle CAB = 65°.

So,

=> \angleADC + \angleCAD +\angleDCA = 180° (Angle sum Property.)

=> 90° + 65° + \angleDCA = 180°

=> 155° +\angleDCA = 180°

=> \angleDCA = 180° - 155°

=> \angleDCA = 25°

Hence, we get,

  • \angleDCA = 25°
  • \angleDCB = 65°
  • \angleCDB = 90°
  • \angleACD = 25°
  • \angleADC = 90°.
7 0
3 years ago
Help me please thank you
True [87]

Answer:

-256

Step-by-step explanation:

6 0
3 years ago
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