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3 years ago

A circle with circumference 8 has an arc with a 288 degree central angle

Mathematics

1 answer:

Lapatulllka [165]3 years ago

3 0

Answer:

Step-by-step explanation:

l=8

$\theta=288 \pi /180=72\pi /45=8\pi /5\\\theta=\frac{l}{r} \\r=\frac{l}{\theta}=8 \times 5/(8 \pi )=5/\pi \approx 1.59$

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3 years ago

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The diameter of the average cell in the human body is 1 x 10-5 meters. The diameter of a grain of sand is about 2 x 10-4 meters.

MariettaO [177]

PART A:

Scientific notation is given by A×10ⁿ where A is any number in a unit and 'n' is an integer.

0.000025 = 2.5×10⁻⁵

PART B:

Diameter of grain of sand ÷ Diameter of human body average cell
(2×10⁻⁴) ÷ (1×10⁻⁵)
(2÷1) × (10⁻⁴÷10⁻⁵)
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PART C:

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PART D:

Smallest bacteria = 300 nanometer
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PART E:

Laws of exponents that are applied in scientific notation is

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3 years ago

A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is

Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

$\Delta s = s_2-s_1$

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

$\Delta x = x_2-x_1$

So we can use the given points $P1:(x_1,y_2) \text{ and } P_2: (x_2,y_2)$ on the displacement formula

$\Delta x = 15-4\\\Delta x = 11$

In the same manner we can look at the y components of those points to find the vertical displacement

$\Delta y = 17-8\\\Delta y =9$

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

$\tan(\theta) = \cfrac{\Delta y}{\Delta x}$

Solving for the angle we get

$\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)$

Replacing values

$\theta = \tan^{-1}\left(\cfrac{9}{11}\right)$

Which give us

$\theta = 39.3^\circ$

So the projection angle is 39.3 degrees.

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3 years ago

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Can someone please help I will be giving Brainliest to whoever can answer :)

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H ⇒ x² - 3x + 2 ≤ 0
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<h3>What is a graph?</h3>

A graph can be defined as a type of chart that's commonly used to graphically represent data on both the horizontal and vertical lines of a cartesian coordinate, which are the x-axis and y-axis.

<h3>What is an inequality?</h3>

An inequality can be defined as a mathematical relation that compares two (2) or more integers and variables in an equation based on any of the following arguments:

Less than (<).
Greater than (>).
Less than or equal to (≤).
Greater than or equal to (≥).

In Geometry, if the leading coefficient of a quadratic equation is greater than (>) zero, the parabolic curve would open upward while the parabolic curve would open downward when the leading coefficient of a quadratic equation is less than (<) zero.

Read more on graph of inequalities here: brainly.com/question/24372553

#SPJ1

Complete Question:

Match the questions with the graphs that are labeled A-H. (keep in mind that some questions might have the same answer)

1. A = {(x, y): y > x^2}

2. B = {(x, y): y ≥ x^2+ 3}

3. C = {(x, y): y ≤ 3x^2 + 2}

4. D = {(x, y): y ≥ 2x^2- 5x + 1}

6. x^2- 3x ≥ 0

7. x^2- 3x + 2 ≤ 0

8. {(x, y): y ≤ 1 - x^2}

9. {(x, y): y ≥ -1}

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1 year ago