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Shalnov [3]
3 years ago
11

7 less than three fifths of b is a

Mathematics
2 answers:
Rina8888 [55]3 years ago
7 0
The answer is 3/5b-7=a.
-BARSIC- [3]3 years ago
3 0
<span>7 less than three fifths of b is a:

3/5b - 7 = a

Hope it helps!</span>
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Edwin needs to buy a car, a truck, and a motorcycle for his shipping business. He wants the car to be red or yellow; the truck t
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We can solve problems like this using multiplication rules. Since the order of colors and combinations does not matter, we can multiply all  values in any order we so choose. In this case, our values are colors and vehicles:

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The length of human pregnancies from conception to birth follows a distribution with mean 266 days and standard deviation 15 day
Katena32 [7]

Answer:

a) 81.5%

b) 95%

c) 75%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 266 days

Standard Deviation, σ = 15 days

We are given that the distribution of  length of human pregnancies is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(between 236 and 281 days)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{281-266}{15})\\\\= P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.838 - 0.023 = 0.815 = 81.5\%

b) a) P(last between 236 and 296)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{296-266}{15})\\\\= P(-2 \leq z \leq 2)\\\\= P(z \leq 2) - P(z < -2)\\= 0.973 - 0.023 = 0.95 = 95\%

c) If the data is not normally distributed.

Then, according to Chebyshev's theorem, at least 1-\dfrac{1}{k^2}  data lies within k standard deviation of mean.

For k = 2

1-\dfrac{1}{(2)^2} = 75\%

Atleast 75% of data lies within two standard deviation for a non normal data.

Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.

7 0
3 years ago
What is the difference of 85.23 and 2.675?
Norma-Jean [14]

Answer: 82.555

Step-by-step explanation: I used a calculator

6 0
3 years ago
How to start the problem off. (substitution)
otez555 [7]
Do you have to use substitution? 
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3 years ago
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